What is the number of hydrogen atoms in 39.6 g of ammonium sulphate, (NH4)2SO4?
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Chemistry
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University
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Hard

Sinqobile Kosiki
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15 questions
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1.
MULTIPLE CHOICE QUESTION
10 mins • 4 pts
3.78 x 10^22
5.91 x 10^21
2.56 x 10^23
1.44 x 10^24
Answer explanation
Calculate the molar mass of (NH4)2SO4.
Convert the given mass of ammonium sulfate (39.6 g) to moles.
Use the mole ratio between (NH4)2SO4 and hydrogen atoms to find the number of moles of hydrogen.
Convert the moles of hydrogen to atoms.
Let's begin:
The molar mass of (NH4)2SO4 can be calculated as follows: Molar mass of NH4 = 14.01 (molar mass of nitrogen) + 4(1.008) (molar mass of hydrogen) = 14.01 + 4.032 = 18.042 g/mol Molar mass of SO4 = 32.07 (molar mass of sulfur) + 4(16.00) (molar mass of oxygen) = 32.07 + 64.00 = 96.07 g/mol Molar mass of (NH4)2SO4 = 2(18.042) + 96.07 = 36.084 + 96.07 = 132.154 g/mol
Now, let's convert the given mass of ammonium sulfate to moles: Number of moles = Mass / Molar mass = 39.6 g / 132.154 g/mol ≈ 0.2995 moles
From the formula (NH4)2SO4, we can see that there are 8 hydrogen atoms for every mole of (NH4)2SO4.
So, the number of hydrogen atoms = 8 * 0.2995 ≈ 2.396
Since we have calculated the number of hydrogen atoms in moles, we need to convert this to atoms by multiplying by Avogadro's number:
2.396×6.022×10232.396×6.022×1023
This calculation gives us approximately 1.44×10241.44×1024.
So, the correct answer is 1.44 x 10^24.
2.
MULTIPLE CHOICE QUESTION
10 mins • 6 pts
What is the empirical formula of a compound composed of 52.14% carbon, 13.13% hydrogen, and 34.73% oxygen by mass?
C2H6O
C6H18O3
C3H8O2
C4H10O3
Answer explanation
Convert the percentages to grams. Assume we have 100 grams of the compound, so we'll have 52.14 g of carbon, 13.13 g of hydrogen, and 34.73 g of oxygen.
Convert the masses of each element to moles using their respective molar masses:
Carbon (C): 52.14 g / 12.01 g/mol ≈ 4.34 moles
Hydrogen (H): 13.13 g / 1.008 g/mol ≈ 13.02 moles
Oxygen (O): 34.73 g / 16.00 g/mol ≈ 2.17 moles
Divide each number of moles by the smallest number of moles to find the simplest whole-number ratio. In this case, oxygen has the smallest number of moles, so we divide all moles by 2.17:
Carbon: 4.34 moles / 2.17 ≈ 2
Hydrogen: 13.02 moles / 2.17 ≈ 6
Oxygen: 2.17 moles / 2.17 = 1
The simplest whole-number ratio of atoms is approximately C2H6O.
3.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
What is the molar mass of Ca(NO3)2?
164.09 g/mol
164.10 g/mol
164.11 g/mol
164.12 g/mol
4.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Balance the equation: C3H8 + O2 -> CO2 + H2O
C3H8 + 5 O2 -> 3 CO2 + 4 H2O
C3H8 + 5 O2 -> 3 CO2 + 4 H2O
C3H8 + 5 O2 -> 3 CO2 + 5 H2O
C3H8 + 4 O2 -> 3 CO2 + 5 H2O
5.
MULTIPLE CHOICE QUESTION
5 mins • 2 pts
What is the oxidation state of sulfur in H2SO4?
+2
+4
+6
+8
Answer explanation
In H2SO4 (sulfuric acid), sulfur can have different oxidation states. Let's calculate it:
Let's assign "x" as the oxidation state of sulfur.
The oxidation state of hydrogen (H) is +1 in most compounds, and the oxidation state of oxygen (O) is typically -2.
In H2SO4, we have:
(2×(+1))+ X +4(−2)=0(2×(+1))+x+4(−2)=0
2+ X − 8=02+x−8=0
X −6=0x−6=0
X =+6x=+6
So, the oxidation state of sulfur in H2SO4 is +6.
Therefore, the correct answer is +6.
6.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Balance the equation: H2 + O2 -> H2O
2 H2 + O2 -> 2 H2O
H2 + O2 -> H2O
2 H2 + 2 O2 -> 2 H2O
H2 + 2 O2 -> H2O
7.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
What is the oxidation state of nitrogen in NH3?
-1
+1
-3
+3
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