EOC review Quadratics

1. A quadratic function has a vertex point of (3, 1) and passes through the point (6, -8). Which equation represents the quadratic function?

• y = −x² + 6x − 8
• y = x² − 6x + 10
• y = −x² − 6x − 8
• y = -x² + 6x − 10

2. Which function is equivalent to y = 3(x + 2)²+ 7?

• y = 3x² + 12x + 33
• y = 3x² + 12x + 19
• y = 3x² + 19
• y = 3x² + 33

3. The robotics class launched a drone from a small platform on the ground. The graph shows the flight of the drone as a function of time elapsed before the drone lands on the ground. Which equation in vertex form represents this function?

• f(t) = 25(t + 1.75)² + 50
• f(t) = 16(t + 1.75)² + 50
• f(t) = -50(t + 3)² + 25
• f(t) = -16(t - 1.75)² + 50

4. A quadratic function is shown below. Which function can be used to represent the graph?

• f(x) = x² + 6x + 5
• f(x) = x² + 4x - 5
• f(x) = x² - 4x - 5
• f(x) = x² - 6x + 5

5. The solutions to a quadratic equation are {2/3, -5/4}. Which function best represents the related quadratic function?

• g(x) = 12x² − 7x − 10
• g(x) = 10x² − 7x − 12
• g(x) = 12x² + 7x − 10
• g(x) = 10x² + 7x − 12

6. The graph of a quadratic function is shown on the grid. Which function is best represented by this graph?

• h(x) = x² − 3x − 9
• h(x) = x² + 3x − 9
• h(x) = x² − 6x
• h(x) = x² + 6x

Tags

CCSS.HSF-IF.C.7A

7. The graph of a quadratic function is shown on the grid. Which function is best represented by this graph?

• f(x) = x² + 3x − 4
• f(x) = -x² − 3x + 4
• f(x) = x² - 3x − 4
• f(x) = -x² + 3x + 4

Tags

CCSS.HSF-IF.C.7A

8. When y = x²+ 9x + 20 is graphed, what will the "zeros" of the graph be?

• 10, 2
• 4.76, -3.82
• -5, -4
• the graph will have no zeros

Tags

CCSS.HSF-IF.C.7A

9. The graph of quadratic function g is shown below. Based on the graph, between which two values of x is a zero of g located?

• -9 and -8
• 1 and 2
• -7 and -5
• 4 and 5

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

10. Which statement about f(x) = 2x² − 3x − 5 is true?

• The zeros are -5/2 and -1, because f(x) = (x + 1)(2x + 5)
• The zeros are -5/2 and 1, because f(x) = (x - 1)(2x + 5)
• The zeros are -1 and 5/2, because f(x) = (x + 1)(2x - 5)
• The zeros are 1 and 5/2, because f(x) = (x - 1)(2x - 5)

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A