4/19(F): Chemistry Checkpoint #42

Match the following units with the appropriate answer based off the information below:


As a 15.1-gram sample of a metal absorbs 48.75 J of heat, its temperature increases 25.0K. What is the specific heat capacity of the metal?

• Q

• x

• ΔT

• 15.1g

• mass

• 48.75J

• c

• 25K

What is the correct numerical setup?


As a 15.1-gram sample of a metal absorbs 48.75 J of heat, its temperature increases 25.0K. What is the specific heat capacity of the metal?

• x=(15.1g)(48.75J)(25.0K)

• 25.0K=(15.1g)(48.75J)(x)

• 48.75J=
  (15.1g)(x)(25.0K)

As a 15.1-gram sample of a metal absorbs 48.75 J of heat, its temperature increases 25.0K. What is the specific heat capacity of the metal? Make sure to have a piece of scrap paper and a calculator, as some algebra is involved.

• 0.129 J/g*K

• 1.95 J/g*K

• 3.23 J/g*K

• 7.74 J/g*K

What table has the specific heat of water?

• Table A

• Table B

• Table C

• Table D

What is the specific heat of water?

• 4.18J/g*K

• 334J/g

• 2260J/g

• 101.3kPa

What is heat of fusion?

• 4.18J/g*K

• 334J/g

• 2260J/g

• 101.3kPa

What is heat of vaporization?

• 4.18J/g*K

• 334J/g

• 2260J/g

• 101.3kPa

What happens to the boiling point as air pressure decreases?

• Boiling point increases

• Boiling point decreases

• It is easier to boil water at sea level
  (high air pressure)

• It is easier to boil water 10,000 feet above sea level (low air pressure)

Where can you find this equation?

• Table A

• Table T

• Table B

• Table D

Which equation would you use to solve the following: Calculate the heat necessary to change 10 g of ice(s) at 0°C to 10 g of water(l) at 0°C.

• q=mCΔT

• q= mH_f

• q= mH_v

• P1V1/T1=P2V2/T2