Solve Quadratic Equations by Factoring

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B

Which equation matches these solutions? x=5,-7

• (x+5)(x-7)=0
• (x-5)(x+7)=0
• (x+5)(x+7)=0
• (x-5)(x-7)=0

Tags

CCSS.HSA-REI.B.4B

Find the zeros of this quadratic.

• b=4/5, b=3
• b=4, b=-3
• b=1/5, b=3
• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

x² + 4x - 32 = 0

• x= -8, 4

• x= 8, -4

• x= -8, -4

• x = -2, 16

Tags

CCSS.HSA-REI.B.4B

6x² - x - 2 = 0

• x= -2/3, 1/2

• x= 2/3, -1/2

• x= -2/3, -1/2

• x = -4, 3

Tags

CCSS.HSA-REI.B.4B

x² = 18x - 81

• x= -9

• x= 9

• x= -9, 9

• x = -81, 18

Tags

CCSS.HSA-REI.B.4B

Solve

3x² + 5x = 12

• x = -4/3, x = 3

• x = 4/3, x = -3

• x = -1, x = 4

• x = 1, x = -4

Tags

CCSS.HSA-REI.B.4B

x²-14x-51=0

• x= 17, -3

• x= -17, 3

• x= -17, -3

Tags

CCSS.HSA-REI.B.4B

4x²+7x-17=3x²+12x-3

• x= -7, -2

• x= 7, -2

• x= -7, 2

Tags

CCSS.HSA-REI.B.4B

3x²+9x-30=0

• x= 2, -5

• x= 5, -2

• x= -5, -2

Tags

CCSS.HSA-REI.B.4B