Using Binomial Probabilities

Given p = 0.457 and n = 60

• 0.543

• σ

• 0.039

• q

• 27.42

• P(x < 42)

• 0.99988

• μ

• 3.859

• P(x = 22)

Given p = 0.817 and n = 21

• 0.074

• μ

• 0.926

• σ

• 0.183

• P(x ≤ 14)

• 17.157

• q

• 1.772

• P(x > 14)

Columbia, SC gets some kind of precipitation about 29.6% of the year. What is the probability that it will rain exactly 10 days in May? (May has 31 days)

• 0.144

• 0.856

• 0.705

• 0.295

Columbia, SC gets some kind of precipitation about 29.6% of the year. What is the probability that it will rain at most 10 days in May? (May has 31 days)

• 0.144

• 0.856

• 0.705

• 0.295

Columbia, SC gets some kind of precipitation about 29.6% of the year. What is the probability that it will rain at least 10 days in May? (May has 31 days)

• 0.144

• 0.439

• 0.705

• 0.561

Columbia, SC gets some kind of precipitation about 29.6% of the year. What is the probability that it will rain more than 10 days in May? (May has 31 days)

• 0.295

• 0.439

• 0.705

• 0.561

Columbia, SC gets some kind of precipitation about 29.6% of the year. What would the the expected number (μ) of rainy days in May? (May has 31 days)

• About 9 days

• About 29 days

• About 1 day

• About 17 days

Tags

CCSS.HSF-LE.A.1B

Columbia, SC gets some kind of precipitation about 29.6% of the year. Which of the following would be considered an "unusual" number of rainy days in May? (May has 31 days) Select all that apply.

• less than 12 days

• more than 11 days

• less than 4 days

• more than 14 days

Tags

CCSS.6.SP.A.2

A certain tennis player makes a successful serve 70% of the time. Assume that each serve is independent of the others. If she serves 6 times, what is the probability that she gets at most 4 of her serves in?

• 0.744

• 0.256

• 0.420

• 0.580

A certain tennis player makes a successful serve 70% of the time. Assume that each serve is independent of the others. If she serves 6 times, what is the probability that she gets at least 4 of her serves in?

• 0.744

• 0.256

• 0.420

• 0.580