𝑧 = 𝑥 + √𝑥𝑦 funksiyaning aniqlanish sohasini toping. Найдите область
2
определения функции 𝑧 = 𝑥 + √𝑥𝑦. Find the domain of function 𝑧 = 𝑥 + √𝑥𝑦.
математика 1
Quiz
•
Other
•
1st Grade
•
Hard
Mira Seidakbar
FREE Resource
Student preview
50 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
𝑧 = 𝑥 + √𝑥𝑦 funksiyaning aniqlanish sohasini toping. Найдите область
2
определения функции 𝑧 = 𝑥 + √𝑥𝑦. Find the domain of function 𝑧 = 𝑥 + √𝑥𝑦.
{𝑥 ≥ 0
𝑦 ≥ 0
𝑣𝑎 {𝑥 ≤ 0
𝑦 ≤ 0
{𝑥 ≥ 0
𝑦 ≥ 0
𝑣𝑎 {𝑥 ≤ 0
𝑦 > 0
{𝑥 ≥ 0
𝑦 ≥ 0
𝑣𝑎 {𝑥 > 0
𝑦 ≤ 0
{𝑥 ≥ 0
𝑦 < 0
𝑣𝑎 {𝑥 ≤ 0
𝑦 ≤ 0
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Ikki o’zgaruvchili 𝑓(𝑥, y) funksiyaning 𝑥 ga nisbatan xususiy orttirma formulasini toping. Найти формулу частного приращения функции двух переменных 𝑓(𝑥, y) по
𝑥. Find formula of partial increment of a function of two variables 𝑓(𝑥, y) with respect to x.
∆𝑥𝑓 = 𝑓(𝑥 + ∆𝑥; 𝑦) − 𝑓(𝑥; 𝑦)
∆𝑧𝑓 = 𝑓(𝑦 + ∆𝑥; 𝑦) − 𝑓(𝑥; 𝑦)
∆𝑥𝑓 = 𝑓(𝑦 + ∆𝑦; 𝑥) − 𝑓(𝑥; 𝑦)
∆𝑥𝑓 = 𝑓(𝑥 + ∆𝑥; 𝑦) − 𝑓(∆𝑥; 𝑦)
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
. Ikki o’zgaruvchili 𝑓(𝑥, y) funksiyaning to’la differensial formulasini toping. Найти формулу полного дифференциала функции двух переменных 𝑓(𝑥, y). Find the formula for total differential of a function of two variables 𝑓(𝑥, y).
𝑑𝑓 = 𝛛𝑓 𝑑𝑥 + 𝛛𝑓 𝑑𝑦
𝛛𝑥 𝛛𝑦
𝑑𝑓 = 𝛛𝑓 𝑑𝑥 + 𝛛𝑧 𝑑𝑦
𝛛𝑥 𝛛𝑦
𝑑𝑓 = 𝛛𝑓 𝑑𝑦 + 𝛛𝑓 𝑑𝑥
𝛛𝑥 𝛛𝑦
𝑑𝑓 = 𝛛𝑓 𝑑𝑥 + 𝛛𝑦 𝑑𝑦
𝛛𝑥 𝛛𝑓
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
48. 𝑧 = x𝑦 funksiyaning 𝛛
𝛛𝑥
xususiy hosilasini toping. Найдите частную
производную 𝛛𝑧
𝛛𝑥
функции 𝑧 = x𝑦. Find the partial derivative 𝛛
𝛛𝑥
of the function
𝑧 = x𝑦.
𝛛𝑧 = 𝑦
𝛛𝑥
𝛛𝑧 = −𝑦
𝛛𝑥
𝛛𝑧 = 𝑥
𝛛𝑥
𝛛𝑧 = −𝑥𝑠
𝛛𝑥
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
47. 𝑧 = 𝑥3 − 𝑦3 funksiyaning 𝛛𝑧
𝛛𝑦
xususiy hosilasini toping. Найдите частную
производную 𝛛𝑧
𝛛𝑦
функции 𝑧 = 𝑥3 − 𝑦3. Find the partial derivative 𝛛𝑧
𝛛𝑦
of the function
𝑧 = 𝑥3 − 𝑦3.
𝛛𝑧 = −3𝑦2
𝛛𝑦
𝛛𝑧 = −3𝑦−2
𝛛𝑦
𝛛𝑧 = 𝑦2
𝛛𝑦
𝛛𝑧 = 3𝑦2
𝛛𝑦
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
44. 𝑢 = 𝑒𝑦𝑥 funksiyaning xususiy hosilalarini toping. Найдите частные производные функции 𝑢 = 𝑒𝑦𝑥. Find the partial derivatives of a function 𝑢 = 𝑒𝑦𝑥.
𝑧′ = y𝑒𝑥𝑦, 𝑧′ = x𝑒𝑥𝑦
𝑥 𝑦
𝑧′ = −y𝑒𝑥𝑦, 𝑧′ = x𝑒𝑥𝑦
𝑥 𝑦
𝑧′ = yx𝑒𝑥𝑦, 𝑧′ = x𝑒𝑥𝑦
𝑥 𝑦
𝑧′ = x𝑒𝑥𝑦, 𝑧′ = y𝑒𝑥𝑦
𝑥 𝑦
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
41. 𝑢 = 𝑥𝑦 + 𝑦 funksiyaning xususiy hosilalarini toping. Найдите частные производные функции 𝑢 = 𝑥𝑦 + 𝑦. Find the partial derivatives of a function
𝑢 = 𝑥𝑦 + 𝑦.
𝑢′ = y, 𝑢′ = 𝑥 + 1
𝑥 𝑦
𝑢′ = y, 𝑢′ = 𝑥 − 1
𝑥 𝑦
𝑢′ = −y, 𝑢′ = 𝑥 + 1
𝑥 𝑦
𝑢′ = y, 𝑢′ = 1
𝑥 𝑦
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