Input Commands Quiz

What is the correct syntax to read a string input from the user in Python?

• `input_string = input()`

• `input_string = read()`

• `input_string = get_input()`

• `input_string = read_input()`

How do you read an integer input from the user in Python?

• `input_integer = int(input())`

• `input_integer = input(int())`

• `input_integer = get_int()`

• `input_integer = read_int()`

Which of the following commands is used to read a float input from the user in Python?

• `input_float = float(input())`

• `input_float = input(float())`

• `input_float = get_float()`

• `input_float = read_float()`

In pseudocode, how would you read a user input and store it in a variable named `userInput`?

• `userInput = INPUT()`

• `userInput = READ()`

• `userInput = GET()`

• `userInput = INPUT`

What will happen if the user inputs a string when the program expects an integer in Python?

• The program will crash with a ValueError.

• The program will convert the string to an integer automatically.

• The program will ignore the input.

• The program will store the string as an integer.

How can you handle input errors in Python to prevent the program from crashing?

• Using a try-except block.

• Using an if-else statement.

• Using a while loop.

• Using a for loop.

Which of the following is an example of handling input errors in Python?

• ```python try: user_input = int(input()) except ValueError: print("Invalid input. Please enter an integer.") ```

• ```python if input() == int: user_input = input() else: print("Invalid input.") ```

• ```python while True: user_input = int(input()) if user_input: break ```

• ```python for i in range(3): user_input = int(input()) ```

In pseudocode, how would you handle an input error when expecting an integer?

• ``` TRY userInput = INPUT userInput = INTEGER(userInput) CATCH PRINT "Invalid input. Please enter an integer." END TRY ```

• ``` IF INPUT == INTEGER THEN userInput = INPUT ELSE PRINT "Invalid input." END IF ```

• ``` WHILE TRUE userInput = INPUT IF userInput == INTEGER THEN BREAK END IF END WHILE ```

• ``` FOR i = 1 TO 3 userInput = INPUT END FOR ```

In pseudocode, how would you prompt the user for their age and then print it?

• ``` PRINT "Enter your age: " age = INPUT PRINT "Your age is " + age ```

• ``` PRINT "Enter your age: " age = INPUT PRINT "Your age is age" ```

• ``` PRINT "Enter your age: " age = INPUT PRINT "Your age is " + INPUT ```

• ``` PRINT "Enter your age: " age = INPUT PRINT "Your age is " + "age" ```

What is the output of the following Python code if the user inputs "25"? ```python age = input("Enter your age: ") print("You are " + age + " years old.") ```

• `You are 25 years old.`

• `You are age years old.`

• `You are 25.0 years old.`

• `You are 25 years old`