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First-Order Logic Quiz

Authored by Rinisha Bagaria

Science

12th Grade

Used 1+ times

First-Order Logic Quiz
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17 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main limitation of Propositional Logic?

Can't represent patterns or regularities

Can't directly talk about properties of individuals or relations between individuals

Can identify individuals like Mary or 3

Can represent generalizations easily

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does First-Order Logic add to Propositional Logic?

Connectives and quantifiers

Only quantifiers

Only variables

Relations, variables, and quantifiers

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can the sentence 'Every elephant is gray' be represented in First-Order Logic?

∃x (elephant(x) ^ gray(x))

x (elephant(X) ^ white(X))

x (elephant(x) ^gray(x))

∃x (elephant(x) ^gray(x))

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of skolem constant in Existential instantiation?

To replace the variable with a new constant not occurring in the KB

To replace the variable with a new variable symbol

To replace the variable with any constant in the KB

To replace the variable with a constant symbol

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which quantified inference rule allows inferring P(c) from (x) P(x)?

Existential generalization

Universal generalization

Existential instantiation

Universal instantiation

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the correct translation of 'All purple mushrooms are poisonous' to First-Order Logic?

x (mushroom(x) ^purple(x)) →poisonous(x)

x purple(x) ^mushroom(x) →poisonous(x)

∃x (mushroom(x) ∃purple(x)) →∃poisonous(x)

∃x ∃y mushroom(x) purple(x) mushroom(y) purple(y) ^ (x=y) z (mushroom(z) purple(z)) →((x=z) (y=z))

7.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

What is the correct translation of 'There are exactly two purple mushrooms' to First-Order Logic?

∃x ∃y mushroom(x) ^purple(x) ^mushroom(y) ^purple(y) ^ (x=y) ^ ∀z (mushroom(z) ^purple(z)) →((x=z) v (y=z))

∀x ∀y mushroom(x) ^purple(x) ^mushroom(y) purple(y) ^ (x=y) ∃z (mushroom(z) ^purple(z)) →((x=z) (y=z))

∀x ∀y mushroom(x) purple(x) ^mushroom(y) v purple(y) ^ (x=y) ∃z (mushroom(z) ^purple(z)) →((x=z) (y=z))

∃x ∃y mushroom(x) ^ purple(x) v mushroom(y) v purple(y) ^(x=y) v z (mushroom(z) v purple(z)) →((x=z) (y=z))

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