
数学习题
Quiz
•
Mathematics
•
6th - 8th Grade
•
Easy
LEE HAW MIN Lee Haw Min
Used 5+ times
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30 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
展开(x+1)2
x2 + 2
x2 + 1
x2 + 2x - 1
x2 + 2x + 1
Answer explanation
To expand (x+1)^2, we use the formula (a+b)^2 = a^2 + 2ab + b^2. In this case, a=x and b=1. Therefore, (x+1)^2 = x^2 + 2x + 1, which matches the option x^2 + 2x + 1.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
展开(x+3)(3x-5)
3x2+14x-15
3x2-14x-15
3x2+4x-15
3x2-4x-15
Answer explanation
To expand (x+3)(3x-5), use the distributive property. First, multiply x by 3x and x by -5 to get 3x^2-5x. Then, multiply 3 by 3x and 3 by -5 to get 9x-15. Combine like terms to get 3x^2+9x-5x-15 = 3x^2+4x-15.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
已知8a=5, 4b=6, 求23a+2b
32
30
24
无解
Answer explanation
To find 2^(3a+2b), we substitute the given values: 8^a = 5 -> 2^(3a) = 5, 4^b = 6 -> 2^(2b) = 6. Therefore, 2^(3a+2b) = 2^(3a) * 2^(2b) = 5 * 6 = 30. Hence, the correct answer is 30.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
展开(x+y)(x-y)(x2+y2)(x4+y4)(x8+y8)
x30 - y30
x16 - y16
x15 - y15
x14 - y14
Answer explanation
To expand the given expression, we can use the difference of squares formula multiple times. After simplifying, we get x^16 - y^16 as the result.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
1+2+3+4+5+6+....+997+998+999+1000=?
500500
50000
55000
50500
Answer explanation
The sum of the first n natural numbers is given by the formula n*(n+1)/2. Here, n=1000. So, the sum is 1000*1001/2 = 500500. Therefore, the correct answer is 500500.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
因式分解x2-3x+2
(x+2)(x-1)
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
因式分解x128-y128
(x64 + y64)(x32 + y32)(x8 + y8)(x4 + y4)(x2+ y2)(x + y)(x - y)
(x64 + y64)(x16 + y16)(x8 + y8)(x4 + y4)(x2 + y2)(x + y)(x - y)
(x64 + y64)(x32+ y32)(x16 + y16)(x8 + y8)(x4 + y4)(x2 + y2)(x + y)(x - y)
(x32 + y32)(x16 + y16)(x8 + y8)(x4 + y4)(x2 + y2)(x + y)(x - y)
Answer explanation
The correct choice is (x^64 + y^64)(x^32+ y^32)(x^16 + y^16)(x^8 + y^8)(x^4 + y^4)(x^2 + y^2)(x + y)(x - y) as it correctly factors x^128 - y^128.
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