CCSS.Math.Content.HSA.APR.B.2

What is the proper way to write the answer for the following problem? 

• 2x³-x²-25x-12
• 2x⁴-x³-25x²-12x+0

Tags

CCSS.Math.Content.HSA.APR.B.2

Factor:
x² - 49

• (x + 7)(x - 7)
• (x + 7)²
• (x - 7)²
• (x+7)(x-1)

Tags

CCSS.Math.Content.HSA.APR.B.2

The polynomial p(x) = 6x³-22x²-47x+27 is given, which conclusion is valid if p(5) = -8

• (x-5) is a factor of p(x)
• (x+8) is a factor of p(x)
• The remainder of p(x) divided by (x-5) is -8
• The remainder of p(x) divided by (x+5) is -8

Tags

CCSS.Math.Content.HSA.APR.B.2

Factor:
v² + 3v - 88

• (v + 11)(v - 8)
• (v + 22)(v - 4)
• (v + 8)(v - 11)
• (v - 22)(v + 4)

Tags

CCSS.Math.Content.HSA.APR.B.2

Factor:
x² - 9

• (x + 3)(x - 3)
• (x + 3)²
• (x - 3)²
• (x+3)(x+3)

Tags

CCSS.Math.Content.HSA.APR.B.2

Factor
x² + 4x + 3

• (x - 1)(x - 3)
• (x + 1)(x + 3)
• (x - 1)(x + 3)
• (x + 1)(x - 3)

Tags

CCSS.Math.Content.HSA.APR.B.2

Factor x² + 7x + 12

• (x + 2)(x + 10)
• (x + 3)(x + 4)
• (x + 4)(x + 5)
• (x + 4)(x + 6)

Tags

CCSS.Math.Content.HSA.APR.B.2

Factor:
 f(x) = x³-12x²+47x-60=0 when 5 is a zero. (so f(5) = 0)

• (x-3)(x-4)(x-5)=0
• (x+1)(x-4)(x-5)=0
• (x-3)(x-4)(2x-5)=0
• (x-5)(x-4)(x-5)=0

Tags

CCSS.Math.Content.HSA.APR.B.2

Factor:   x³ + 1

• (x + 1)³
• (x+1)(x² - x + 1)
• (x - 1) (x² + x - 1)
• (x + 1)(x² - 2x + 1)

Tags

CCSS.Math.Content.HSA.APR.B.2

Factor t² - 6t + 8

• (t - 4)(t - 6)

• (t + 2)(t + 4)

• (t - 2)(t + 4)

• (t - 2)(t - 4)

Tags

CCSS.Math.Content.HSA.APR.B.2