TEKS.MATH.9-12.VII.C

Since January 1980, the population of the city of Brownville has grown according to the mathematical model y=720,500(1.022)^x, where x is the number of years since January 1980. What is the was the population of Brownville in 1980?

• 102.2 people
• 720,500 people
• 1.022 people
• 1022 people

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TEKS.MATH.9-12.VII.C

Suppose a culture of bacteria begins with 5000 cells and dies by 30% each year. Write an equation that represents this situation.

• y=5000(0.7)^x
• y=30(5000)^x
• y=5000(1.3)^x
• y=5000x^x

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TEKS.MATH.9-12.VII.C

A new savings account is opened with $400 and gains 3% every year. What is the exponential function?

• f(x)=400(1+3)^x
• f(x)=400(1-0.03)^x
• f(x)=400(1+0.03)^x
• f(x)=400(0.03)^x

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TEKS.MATH.9-12.VII.C

A 78 gram sample of Uranium loses half of its mass each year.  What is the exponential equation? 

• y=78(0.5)^x
• y=78(1.5)^x
• y=78(2)^x

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TEKS.MATH.9-12.VII.C

The amount of money that Li spends on video games depends on how many games he purchases.  If Li has at most $90 to spend on games for his Xbox 360 and the games cost $22.50 each, what is the domain of this function?

• {0 ≤ x ≤ 90}
• {0 ≤ x ≤ 4}
• {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
• {0, 1, 2, 3, 4}

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TEKS.MATH.9-12.VII.C

Treasure won $3,000 from a radio contest. If she puts this money in a bank account that earns 2.9% interest compounded quarterly, how much total will she earn in 10 years?

• $4915.59

• $3933.28

• $2979.81

• $4005.09

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TEKS.MATH.9-12.VII.C

The total cost of renting a car is $22 per day, plus an initial fee of $55. Which equation best describes this relationship?

• c = 55d - 22

• c = 55 + 22d

• c = 22d - 55

• c = 22d + 100

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TEKS.MATH.9-12.VII.C

Use the graph to determine the solutions.

• -1 and -3
• 1 and -3
• 1 and 3
• -1 and 3

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TEKS.MATH.9-12.VII.C

Ashleigh put some money into an account paying 4.5% compounded continuously for 10 years. She now has $3567.91 in the account. How much money did she start the account with?

• $2275

• $2725

• $2572

• $3275

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TEKS.MATH.9-12.VII.C

Write an exponential function to model the situation. The value of a car is $18000 and is depreciating at a rate of 12% per year.

• V(t) = .88(18000)^t

• V(t) = .12(18000)^t

• V(t) = 18000(.88)^t

• V(t) = 18000(.12)^t

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TEKS.MATH.9-12.VII.C