Uniformly Accelerated Motion

What are the three equations of motion for uniformly accelerated motion?

• v = u + 2at

• v = u + at, s = ut + 0.5at^2, v^2 = u^2 + 2as

• s = ut + at

• s = ut + at^2

• v = u + t^2

What is the acceleration due to gravity on Earth?

• 10.25 m/s^2

• 9.81 m/s^2

• 6.67 m/s^2

• 8.91 m/s^2

Explain the concept of free fall in the context of uniformly accelerated motion.

• Free fall occurs only in a vacuum environment.

• Free fall is when an object moves upwards due to gravity.

• Free fall in the context of uniformly accelerated motion refers to the motion of an object falling solely under the influence of gravity, experiencing a constant acceleration of approximately 9.81 m/s^2.

• Free fall involves a variable acceleration depending on the object's mass.

How does projectile motion differ from regular motion?

• Projectile motion involves circular motion, while regular motion does not.

• Projectile motion always occurs in a vacuum, while regular motion occurs in air.

• Projectile motion is always linear, while regular motion can be curved.

• Projectile motion involves both horizontal and vertical components of motion, while regular motion usually only involves motion along a single axis.

How can you analyze the motion of an object graphically in uniformly accelerated motion?

• Use a bar graph to represent kinetic energy

• Plot graphs of velocity vs. time and displacement vs. time

• Create a scatter plot of mass vs. time

• Draw a pie chart of acceleration

What is the first equation of motion and how is it derived?

• v = u + at

• v = u + t

• v = u + a

• v = u - at

Calculate the acceleration of an object if it falls freely for 2 seconds.

• 9.81 m/s^2

• 3.56 m/s^2

• 5.67 m/s^2

• 12.34 m/s^2

In projectile motion, what is the horizontal component of velocity called?

• sideways speed

• lateral velocity

• transverse motion

• horizontal velocity

Describe the trajectory of a projectile in motion.

• The trajectory of a projectile in motion is a zigzag pattern.

• The trajectory of a projectile in motion is a perfect circle.

• The trajectory of a projectile in motion is a straight line.

• The trajectory of a projectile in motion is a parabolic path.

How can you determine the maximum height reached by a projectile?

• h = (v * cos(theta)) / g

• h = (v^2 * sin^2(theta)) / (2 * g)

• h = (v * sin(theta)) / g

• h = (v^2 * cos^2(theta)) / (2 * g)