CCSS.Math.Content.HSA.REI.B.4

.How many zeros does this parabola have? 

• 3
• 2
• 0
• 1

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CCSS.Math.Content.HSA.REI.B.4

Solve
4m² - 100 = 0

• m=25, -25
• m=96
• m=5, -5
• m=-96

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CCSS.Math.Content.HSA.REI.B.4

In the quadratic formula, if b²-4ac>0, then the quadratic equation has

• two imaginary solutions
• two different real solutions
• two equal real solutions
• none of these

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CCSS.Math.Content.HSA.REI.B.4

Solve the equation by completing the square and then finding the roots. 
x²+ 6x - 4 = 36

• x = -7, 7
• x = 4, -10
• x = -4 +- √7
• x = 10, -4

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CCSS.Math.Content.HSA.REI.B.4

In the equation ax²+bx+c=0, the x² term always corresponds with 

• a
• b
• c

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CCSS.Math.Content.HSA.REI.B.4

The quadratic equation can be used to solve quadratic equations that cannot be factored.

• True
• False

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CCSS.Math.Content.HSA.REI.B.4

(x + 1) ² = 25

• ± 5
• 4  or  -6
• -4  or  6
• ± 4

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CCSS.Math.Content.HSA.REI.B.4

If the discriminant is positive, then the solution will be

• one real solution

• two real solutions

• no real solutions

• one imaginary solution

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CCSS.Math.Content.HSA.REI.B.4

2d² = 8

• 4
• -2
• -4, 4
• -2, 2

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CCSS.Math.Content.HSA.REI.B.4

How do you find the vertex?

y = ax² + bx + c

• x = -b/(2a) and plug back in for y

• x = b/(2a) and plug back in for y

• x = -b/a and plug back in for y

• x = b/a and plug back in for y

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CCSS.Math.Content.HSA.REI.B.4