CCSS.Math.Content.HSA.REI.B.4

If we have the equation y=ax²+bx+c, how can we can find the x-coordinate of the vertex?

• -a
• -b/a
• b/2a
• -b/2a

Tags

CCSS.Math.Content.HSA.REI.B.4

What is the first step to solving THIS equation by completing the square?
a² + 10a + 21 = 0

• Set the equation equal to zero
• Divide 10 by 2 and add the result to both sides
• Add a² and 10a together
• Subtract the 21

Tags

CCSS.Math.Content.HSA.REI.B.4

What is one of the solutions to this equation?
(2x - 1)² = 49

• 7
• -7
• -4
• -3

Tags

CCSS.Math.Content.HSA.REI.B.4

What are the solutions?

• 0 and 8
• -2 and -4
• 3 and -1
• 2 and 4

Tags

CCSS.Math.Content.HSA.REI.B.4

What are the x- intercepts?

• x= 0 and x= -4
• x= 0 and x= 4
• y= 0
• x= 2

Tags

CCSS.Math.Content.HSA.REI.B.4

How many zeros does this parabola have? 

• 3
• 2
• 0
• 1

Tags

CCSS.Math.Content.8.F.A.1

CCSS.Math.Content.HSA.REI.B.4

What is the discriminant of 6x² − 2x − 3 = 0

• 76

• 29

• 68

• none of these

Tags

CCSS.Math.Content.HSA.REI.B.4

Solve for 0≤x≤2π

2cos²x + cosx = 0

• π/2, 3π/2

• 0, π,2π

• 2π/3, 4π/3

• π/3, 5π/3

Tags

CCSS.Math.Content.HSA.REI.B.4

An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation

s(t) = –16t² + 64t + 80

What will be the object's maximum height?

• 2 ft

• 80 ft

• 144 ft

• 64 ft

Tags

CCSS.Math.Content.HSA.REI.B.4

Determine the values of a, b, and c for the quadratic equation:

4x² – 8x = 3

• a = 4, b = -8, c = 3

• a = 4, b =-8, c =-3

• a = 4, b = 8, c = 3

• a = 4, b = 8, c = -3

Tags

CCSS.Math.Content.HSA.REI.B.4