CCSS.Math.Content.HSG.GPE.A.1

What is the radius of the circle with equation x² + y² = 1?

• 0
• 0.5
• 1
• 2

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CCSS.Math.Content.HSG.GPE.A.1

See Picture

• A
• B
• C
• D

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CCSS.Math.Content.HSG.GPE.A.1

Write the equation of a circle with center (7, 0) with radius 3. 

• (x - 7)² + y² = 9
• x² + (y -7)² = 9
• (x - 7)² + y² = 3
• x² + (y -7)² = 3

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CCSS.Math.Content.HSG.GPE.A.1

Write the equation of a circle with center (7, 0) with radius 3. 

• (x - 7)² + y² = 9
• x² + (y -7)² = 9
• (x - 7)² + y² = 3
• x² + (y -7)² = 3

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CCSS.Math.Content.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the radius of the circle is...

• 4
• 2
• 3
• 16

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CCSS.Math.Content.HSG.GPE.A.1

What is the radius of the circle
(x+7)²+(y-2)²=144?

• 7
• 12
• 13

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CCSS.Math.Content.HSG.GPE.A.1

In the equation
(x+2)²+(y+3)²=49, what is the center of the circle?

• (2, 3)
• (3, 2)
• (-3, -2)
• (-2, -3)

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CCSS.Math.Content.HSG.GPE.A.1

The endpoints of a diameter of a circle are (3,1) and (9,5).Find the equation of the circle?
Hint: In this problem, we are not given the center or radius however we can find the length of the diameter using the distance formula (Phythagoras) and then divide it by 2. The center is simply the midpoint of the given points.

• (x−6)²+(y−3)²=13
• (x−3)²+(y−6)²=13²
• (x−5)²+(y−9)²=13
• (x−9)²+(y−5)²=169/4

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CCSS.Math.Content.HSG.GPE.A.1

Find the equation of the circle with center (−8,3) and (2,−5) is on the circle?
Hint: you need to find the radius by plugging in values for four variables 
x=
y=
h=
k=
in (x-h)²+(y-k)²=r²

• (x+8)²+(y−3)²=164^.5.
• (x+3)²+(y−8)²=164.
• (x)²+(y)²=164.
• (x+8)²+(y−3)²=164.

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CCSS.Math.Content.HSG.GPE.A.1

Which graph corresponds to

(x-4)²+ (y+4)²=25

• A

• B

• C

• D

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CCSS.Math.Content.HSG.GPE.A.1