TEKS.MATH.9-12.II.C

38 + 7k = 8(k + 4)

• 6
• 8
• -6
• 1

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TEKS.MATH.9-12.II.C

What is the first step to solving THIS equation by completing the square?
a² + 10a + 21 = 0

• Set the equation equal to zero
• Divide 10 by 2 and add the result to both sides
• Add a² and 10a together
• Subtract the 21

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TEKS.MATH.9-12.II.C

A diver is standing on a platform above the pool. He jumps form the platform with an initi8al upward velocity of 8 ft/s. Use the formula h t = −16 t² + 8t + 24, where h is his height above the water, t is the time, v is his starting upward velocity, and s is his starting height. How high is the platform?

• .25 ft
• 24 ft
• 25 ft
• 8 ft

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TEKS.MATH.9-12.II.C

-8(8x+11)=488

• x=9
• x=-9
• x=-15
• x=12

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TEKS.MATH.9-12.II.C

Find a₂₆ in the arithmetic sequence: -15, -35, -55, -75, ...

• -515
• -490
• -535
• 460

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TEKS.MATH.9-12.II.C

Solve by factoring.
z² - 6z - 27 = 0

• z = 3 or z = 9
• z = 3 or z = -9
• z = -3 or z = 9
• z = -3 or z = -9

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TEKS.MATH.9-12.II.C

Solve using substitution.
x - 2y = 2
3x + 4y = 3

• (1.4, -0.3)
• (3.1, 5)
• (-2.5, 3.5)
• (6.9, 1.02)

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TEKS.MATH.9-12.II.C

An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation 
s(t) = –16t² + 64t + 80.
What will be the object's maximum height? 

• 2 ft
• 80 ft
• 144 ft
• 64 ft

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TEKS.MATH.9-12.II.C

Janice puts a fence around her rectangular garden. The garden has a length that is 9 feet less than 3 times its width. What is the perimeter of Janice's fence if the area of her garden is 5,670 square feet? 

• 342 feet 
• 318 feet 
• 300 feet 
• 270 feet 

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TEKS.MATH.9-12.II.C

⅖(x + 3)² + 8 = -32

• x = 3 ± 10i

• x = ±13i

• x = -3 ± 10i

• x = ±i√10

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TEKS.MATH.9-12.II.C