TEKS.MATH.9-12.III.C.1

BE = 15. Find EG.

• 10
• 5
• 22.5
• 20

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TEKS.MATH.9-12.III.C.1

What is the midpoint between (3, -1) and (7, -5)

• (5, -2)
• (10, -6)
• (5, -3)
• (2, -2)

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TEKS.MATH.9-12.III.C.1

TEKS.MATH.9-12.VIII.A

What is the x-intercept shown on the graph?

• (2, 0)
• (-2, 0)
• (0, 3)
• (3, 0)

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TEKS.MATH.9-12.III.C.1

Write the equation of the circle.

• (x+1)² + (y +1)² = 3
• (x+1)² + (y -1)² = 3
• (x+1)² + (y +1)² = 9
• (x-1)² + (y -1)² = 9

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TEKS.MATH.9-12.III.C.1

What is the formula above primarily used for?

• Finding the axis of symmetry from standard form
• Finding the vertex from standard form
• Finding the vertex from vertex form
• Finding the vertex from standard form

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TEKS.MATH.9-12.III.C.1

Goes through (3, -4) and (3, 4)

• Zero Slope
• y = 3/4x + 0
• y = 4/3x + 0
• No Slope (Undefined)

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TEKS.MATH.9-12.III.C.1

Write the equation of the circle with center C(-1 , -3) and radius = 6

• ( x + 1 )² + ( y + 3 )² = 12

• ( x - 1 )² + ( y + 3 )² = 36

• ( x - 1 )² + ( y - 3 )² = 36

• ( x + 1 )² + ( y + 3 )² = 36

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TEKS.MATH.9-12.III.C.1

To find the solution(s) for a set of inequalities graphically, you will

• graph the two inequalities and the points of intersection are the solutions.

• graph the two inequalities and see were they cross the x-axis

• graph the two inequalities and the overlapping shading represents the solutions

• graph the two inequalities and the unshaded area is the solution set.

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TEKS.MATH.9-12.III.C.1

Two lines that are parallel will have ...

• Slope that is opposite reciprocals

• No slope

• Slope that is the same

• none of the above

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TEKS.MATH.9-12.III.C.1

What is the equation for this circle?

• (x+1)+(y+1)=9
• x²+y²=9
• x+y=9

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TEKS.MATH.9-12.III.C.1