CCSS.Math.Content.HSF.TF.C.8

Simplify

• csc²θ
• sec²θ
• cscθ
• 1

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CCSS.Math.Content.HSF.TF.C.8

Solve the following for tan²θ:
1 + tan²θ = sec²θ 

• tan²θ = sec²θ + 1
• tan²θ = sec²θ - 1
• tanθ = secθ - 1
• tan²θ = opp/adj

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CCSS.Math.Content.HSF.TF.C.8

Please select the correct solution

• csc² x
• cot² x
• sin² x
• sec² x

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CCSS.Math.Content.HSF.TF.C.8

Is this a pythagorean identity?
tan²x + 1 = secx

• Yes
• No

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CCSS.Math.Content.HSF.TF.C.8

cos(0)

• 1
• 0
• 1/2
• -1

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CCSS.Math.Content.HSF.TF.C.8

-(sin²x + cos²x)

• -1
• 1
• -2
• 2

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CCSS.Math.Content.HSF.TF.C.8

Simplify (Hint: you will need to FOIL first)

• sinθ

• cot²θ

• tan²θ

• cos²θ

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CCSS.Math.Content.HSF.TF.C.8

What quadrant is -2π/3 in?

• I

• II

• III

• IV

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CCSS.Math.Content.HSF.TF.C.8

tanθ is positive in

• the 1st and 2nd quadrants
• the 1st and 3rd quadrants
• the 1st and 4th quadrants
• the 2nd and 3rd quadrants

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CCSS.Math.Content.HSF.TF.C.8

csc x =

• 1/cosx

• 1/sinx

• cot²x-1

• 1/secx

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CCSS.Math.Content.HSF.TF.C.8