
Class_23_08_2024

Quiz
•
Computers
•
University
•
Hard
Dr.R.Vignesh Dr.R.Vignesh
FREE Resource
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
3 mins • 5 pts
What is time complexity of fun()?
int fun(int n)
{
int count = 0;
for (int i = n; i > 0; i /= 2)
for (int j = 0; j < i; j++)
count += 1;
return count;
}
O(n2)
O(n*log(n))
O(n*log(n*Log(n)))
O(n)
2.
MULTIPLE CHOICE QUESTION
3 mins • 5 pts
What is the time complexity of fun()?
int fun(int n)
{
int count = 0;
for (int i = 0; i < n; i++)
for (int j = i; j > 0; j--)
count = count + 1;
return count;
}
Theta (n)
Theta (n2)
Theta (n*log(n))
Theta (n*(log(n*log(n))))
3.
MULTIPLE CHOICE QUESTION
1 min • 5 pts
Which of the given options provides the increasing order of asymptotic complexity of functions f1, f2, f3, and f4?
f1(n) = 2n
f2(n) = n(3/2)
f3(n) = n*log(n)
f4(n) = nlog(n)
f3, f2, f4, f1
f3, f2, f1, f4
f2, f3, f1, f4
f2, f3, f4, f1
4.
MULTIPLE CHOICE QUESTION
3 mins • 5 pts
What is the time complexity of the below function?
void fun(int n, int arr[])
{
int i = 0, j = 0;
for (; i < n; ++i)
while (j < n && arr[i] < arr[j])
j++;
}
O(n*log(n)2)
O(n*log(n))
O(n2)
O(n)
5.
MULTIPLE CHOICE QUESTION
2 mins • 5 pts
In a competition, four different functions are observed. All the functions use a single for loop and within the for loop, same set of statements are executed. Consider the following for loops:
A) for(i = 0; i < n; i++)
B) for(i = 0; i < n; i += 2)
C) for(i = 1; i < n; i *= 2)
D) for(i = n; i <= n; i /= 2)
If n is the size of input(positive), which function is most efficient(if the task to be performed is not an issue)?
A
B
C
D
6.
MULTIPLE CHOICE QUESTION
1 min • 5 pts
What does it mean when we say that an algorithm X is asymptotically more efficient than Y?
X will be a better choice for all inputs
X will be a better choice for all inputs except possibly small inputs
X will be a better choice for all inputs except possibly large inputs
Y will be a better choice for small inputs
7.
MULTIPLE CHOICE QUESTION
3 mins • 5 pts
In the following function, let n >= m.
int gcd(n, m)
{
if (n % m == 0)
return m;
n = n % m;
return gcd(m, n);
}
theta (log(n))
Omega (n)
theta (log(log(n)))
theta (sqrt(n))
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