Quiz Turunan Aljabar (1)

$$y'=6x^2-8x+2$$  

$$y'=6x^2+8x+2$$  

$$y'=6x^3-8x^2$$  

$$y'=6x^2-8x$$  

$$y'=6x^2+8x$$  

$$6x^2-4x-4$$  

$$2x^2-2x-4$$  

$$6x^2-4x-3$$  

$$6x^3-4x^2-4$$  

$$6x^3-4x^2-4x$$  

$$x^5-x^3+3x^2-3$$  

$$5x^4+3x^2+6x$$  

$$5x^4-3x^2+6x$$  

$$5x^4-3x^2-6x$$  

$$x^4-x^2+x$$  

10x² – x – 3

20x – 1

30x² – 12x + 5

30x – 12

5(2x² +1) + 2x(5x-3)

$$x^3+x^2–2$$  

$$x^3+2x^2–4$$  

$$2x^3+2x^2–4$$  

$$2x^3+2x^2–4x$$  

$$2x^3+2x^2–4x+1$$  

f'(x) = -2

f'(x) = 2

f'(x) = x

f'(x) = 1

f'(x) = 0

f'(x) = $$-50x^5$$  

f'(x) = $$-50x^4$$  

f'(x) = $$-10x^4$$  

f'(x) = $$-50x^3$$  

f'(x) = $$-50x^2$$  

f'(x) = $$3x^2-4x\ +6$$  

f'(x) = $$3x^2-2x+6$$  

f'(x) = $$-3x^2-4x+6$$  

f'(x) = $$-3x^2-4x-6$$  

f'(x) = $$-3x^2+x^2+6$$  

$$-\frac{2}{x^3}-6x\ -\frac{15}{x^4}$$  

$$-\frac{2}{x^3}+6x\ +\frac{15}{x^4}$$  

$$-\frac{2}{x^3}-6x\ +\frac{15}{x^4}$$  

$$\frac{2}{x^3}+6x\ +\frac{15}{x^4}$$  

-8

-6

-5

-3

-2