Statistics

Find the mean, median and mode for the following data:

• 36, 39.09, 40

• 25, 34, 44

• 11, 39.1, 44

• 36, 39.09, 44

If the mean of frequency distribution is 7.5 and ∑f_i x_i = 120 + 3k, ∑f_i = 30, then k is equal to

• 40

• 35

• 50

• 45

The class interval of a given observation is 10 to 15, then the class mark for this interval will be

• 12

• 14

• 12.5

• 13.5

If the sum of frequencies is 24, then the value of x in the observation: x, 5,6,1,2, will be

• 10

• 8

• 11

• 4

Construction of a cumulative frequency table is useful in determining the

• Mean

• Median

• Mode

• All of the three measures

While computing mean of grouped data, we assume that the frequencies are

• Centered at the class marks of the classes

• Centered at the upper limits of the classes

• Centered at the lower limits of the classes

• Evenly distributed all over the classes

The method used to find the mean of a given data is (are)

• Direct method

• Assumed mean method

• Step deviation method

• All the above

Mode is the

• Middle most frequent value

• Least frequent value

• Maximum frequent value

• None of these

If 35 is removed from the data, 30, 34, 35, 36, 37, 38, 39, 40 then the median increases by

• 1

• 0.5

• 2

• 1.5

Size of a class intervail is measured by

• (upper limit + lower limit)/2

• (upper limit - lower limit)/2

• upper limit - lower limit

• upper limit - lower limit