Solving Systems of Equations

Solve the system using substitution: 2x + 3y = 12 and x - y = 1.

• (2, 3)

• (1, 4)

• (4, 0)

• (3, 2)

Use elimination to solve: 3x + 4y = 10 and 2x - y = 3.

• (3, 0)

• (1, 2)

• (0, 2)

• (2, 1)

Find x and y using substitution: y = 2x + 1 and 3x - 4y = 5.

• x = -9/5, y = -13/5

• x = 1, y = 3

• x = 0, y = 1

• x = -2, y = -3

Eliminate y to solve: 5x + 2y = 20 and 3x - 2y = 6.

• x = 1.5

• x = 3.25

• x = 4

• x = 2

Use substitution to find the solution: x + y = 7 and y = 3x - 1.

• (1, 6)

• (2, 5)

• (3, 4)

• (0, 7)

Solve using elimination: 4x + y = 9 and 2x - 3y = -1.

• (13/7, 11/7)

• (0, 9)

• (1, 4)

• (2, 5)

Find the values of x and y: 6x + 5y = 30 and 4x - y = 2 using substitution.

• x = 20/13, y = 54/13

• x = 0, y = 6

• x = 10, y = 4

• x = 5, y = 6

Use elimination to solve: 7x + 2y = 14 and 3x + 4y = 18.

• (0, 7)

• (5, 2)

• (1, 3)

• (10/11, 42/11)

Solve the system using substitution: 2y = 4x + 6 and x + y = 8.

• (4, 4)

• (5/3, 19/3)

• (2, 6)

• (3, 5)

Eliminate x to find y: 3x + 5y = 15 and 2x + 3y = 12.

• -2

• 10

• 4

• -6