A basketball is dribbled 20 times in 4 seconds. What is the period + frequency of the bouncing ball? *Answer in that order!

• Period: 5 seconds; Frequency = 0.2 Hz

• Period: 0.2 seconds; Frequency 5 Hertz

• Period 20 seconds; Frequency 4 Hz

• Period: 0.2 Hz; Frequency 5 seconds

Tags

NGSS.HS-PS4-1

An insect can flap its wings around 24,000 times per minute. The period of the wing flap is _______ and its frequency is _________. *Answer in that order!

• The period of the bee flap is 0.25 seconds and its frequency is 40 Hz.

• The period of the bee flap is 24,000 seconds and its frequency is 0.00005 Hz.

• The period of the bee flap is 0.0025 seconds and its frequency is 400 Hz.

• The period of the bee flap is 0.025 seconds and its frequency is 400 Hz.

Tags

NGSS.MS-PS4-1

The mathematical relationship between frequency + period is _______. If an oscillator has a HIGH FREQUENCY it must have a (LARGE/SHORT) period. *Answer in that order!

• The mathematical relationship between frequency + period is inverse. If an oscillator has a HIGH FREQUENCY it must have a SHORT period.
• The mathematical relationship between frequency + period is inverse square. If an oscillator has a HIGH FREQUENCY it must have a SHORT period.

• The mathematical relationship between frequency + period is inverse. If an oscillator has a HIGH FREQUENCY it must have a LONG period.

Mathematical/Solve: An air cart attached to a spring completes FOUR Oscillations every 4.8 seconds. At t = 0, the cart is launched/released from rest at a distance of 60 cm from its equilibrium position. Given: there are 100 centimeters in 1 meter.

Based on the provided information: Which of the following is TRUE?

1. Period of oscillation?

2. Distance traveled 0.6 seconds after launch

3. Distance traveled 0.3 seconds after launch?

4. What is the AMPLITUDE of the cart’s motion?

• The period of oscillation is 1.2 seconds

• After 0.6 seconds the car have moved 1.2 meters

• After 0.3 seconds the car has moved 0.6 meters (60 cm)

• The Amplitude is 0.6 meters

• All answers are TRUE

Tags

NGSS.MS-PS4-1

A mass moves back + forth in simple harmonic motion with an AMPLITUDE of 0.5 m and a PERIOD of 0.4 seconds. Through what distance does the mass move in 1.2 sec?

• 2 meters

• 4 meters

• 6 meters

• 12 meters

A 2.4-kg air-track cart is attached to a spring with a spring constant of 40 Newton-meters and set into motion. What is the period of its oscillation?

• 1.1 seconds

• 1.5 seconds

• 1.8 seconds

• 2.1 seconds

A 0.8-kg mass attached to a spring undergoes simple harmonic motion with a frequency of 0.4 Hz. What is the spring constant of the spring? (Rearrange T=2π√(m/k) to solve for the spring constant k.)

• 4.93 N m

• 5.05 N m

• 5.64 N m

• 5.94 N m

You have a spring with a spring constant of 40 N·m. What mass should you attach to this spring so that its motion has a period of 1.4 s? (Rearrange T=2π√(m/k) to solve for the mass m).

• 1.99 kg

• 2.12 kg

• 2.34 kg

• 3.11 kg

If the mass attached to a spring is decreased and the spring constant is increased, does the period of the oscillating motion increase, decrease, or stay the same?

• Increase

• Decrease

• Stay the same

• There is no way to determine based on the information

Adding a greater mass to a hanging spring, we should expect WHICH of the following to INCREASE when having it oscillate vertically? *You could answer more than one. That is not to say there are.

• Period

• Stretch length

• spring constant (k)

• Frequency