Himpunan penyelesaian dari pertidaksamaan 2 x − 1 4 − x > 0 \frac{2x-1}{4-x}>0 4 − x 2 x − 1 > 0 adalah ...

H P = { 1 2 < x < 4 } HP=\left\{\frac{1}{2}<x<4\right\} H P = { 2 1 < x < 4 }

H P = { 1 2 < x < 2 } HP=\left\{\frac{1}{2}<x<2\right\} H P = { 2 1 < x < 2 }

H P = { 1 4 < x < 2 } HP=\left\{\frac{1}{4}<x<2\right\} H P = { 4 1 < x < 2 }

H P = { 1 4 < x < 1 2 } HP=\left\{\frac{1}{4}<x<\frac{1}{2}\right\} H P = { 4 1 < x < 2 1 }

Penyelesaian pertidaksamaan 5 x − 3 x − 7 ≥ 1 \frac{5x-3}{x-7}\ge1 x − 7 5 x − 3 ≥ 1 adalah .....

x ≤ − 1 x\le-1 x ≤ − 1 atau x > 7 x>7 x > 7

x < − 7 x<-7 x < − 7 atau x > 1 x>1 x > 1

x < − 1 x<-1 x < − 1 atau x ≥ 7 x\ge7 x ≥ 7

− 1 ≤ x < 7 -1\le x<7 − 1 ≤ x < 7

− 7 < x ≤ 1 -7<x\le1 − 7 < x ≤ 1

Himpunan penyelesaian dari 2 x − 7 < 3 \sqrt{2x-7}<3 2 x − 7 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> < 3 adalah .....

{x| 7 2 \frac{7}{2} 2 7 ≤ \le ≤ x < < < 8 }

{x|x ≥ \ge ≥ 7 2 \frac{7}{2} 2 7 }

{x| 7 2 \frac{7}{2} 2 7 < < < x ≤ \le ≤ 8}

Pertidaksamaan 6 x + 7 ≥ 3 x − 2 \sqrt{6x+7}\ge\sqrt{3x-2} 6 x + 7 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> ≥ 3 x − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> dipenuhi oleh .....

x ≥ 2 3 x\ge\frac{2}{3} x ≥ 3 2

x ≥ − 7 6 x\ge-\frac{7}{6} x ≥ − 6 7

x ≤ 2 3 x\le\frac{2}{3} x ≤ 3 2

x ≤ − 6 7 x\le-\frac{6}{7} x ≤ − 7 6

Penyelesaian pertidaksamaan x + 1 2 x − 1 < 3 \frac{x+1}{2x-1}<3 2 x − 1 x + 1 < 3 adalah .....

x < 1 2 x<\frac{1}{2} x < 2 1 atau x > 4 5 x>\frac{4}{5} x > 5 4

x < − 1 2 x<-\frac{1}{2} x < − 2 1 atau x > 4 5 x>\frac{4}{5} x > 5 4

x < − 4 5 x<-\frac{4}{5} x < − 5 4 atau x > 1 2 x>\frac{1}{2} x > 2 1

− 4 5 < x < − 1 2 -\frac{4}{5}<x<-\frac{1}{2} − 5 4 < x < − 2 1

1 2 < x < 4 5 \frac{1}{2}<x<\frac{4}{5} 2 1 < x < 5 4

Himpunan penyelesaian dari pertidaksamaan 2 x − 1 4 − x > 0 \frac{2x-1}{4-x}>0 4 − x 2 x − 1 > 0 adalah ...

H P = { 1 2 < x < 4 } HP=\left\{\frac{1}{2}<x<4\right\} H P = { 2 1 < x < 4 }

H P = { 1 2 < x < 2 } HP=\left\{\frac{1}{2}<x<2\right\} H P = { 2 1 < x < 2 }

H P = { 1 4 < x < 2 } HP=\left\{\frac{1}{4}<x<2\right\} H P = { 4 1 < x < 2 }

H P = { 1 4 < x < 1 2 } HP=\left\{\frac{1}{4}<x<\frac{1}{2}\right\} H P = { 4 1 < x < 2 1 }

Nilai x yang memenuhi pertidaksamaan x − 4 x − 3 ≤ x − 3 x − 2 \frac{x-4}{x-3}\le\frac{x-3}{x-2} x − 3 x − 4 ≤ x − 2 x − 3 adalah ....

x < 2 x<2 x < 2 atau x > 3 x>3 x > 3

− 3 < x < 2 -3<x<2 − 3 < x < 2

x ≤ 2 x\le2 x ≤ 2 atau x > 3 x>3 x > 3

x < − 3 x<-3 x < − 3 atau x < 2 x<2 x < 2

Fungsi Rasional adalah fungsi yang terdiri dari pembilang dan penyebut dalam bentuk

f ( x ) = p ( x ) q ( x ) , d e n g a n q ( x ) ≠ 0 f\left(x\right)=\frac{p\left(x\right)}{q\left(x\right)},\ dengan\ q\left(x\right)\ne0 f ( x ) = q ( x ) p ( x ) , d e n g a n q ( x )  = 0

f ( x ) = p ( x ) . q ( x ) f\left(x\right)=p\left(x\right)\ .\ q\left(x\right) f ( x ) = p ( x ) . q ( x )

f ( x ) = p ( x ) q ( x ) , q ( x ) n i l a i n y a s e m b a r a n g f\left(x\right)=\frac{p\left(x\right)}{q\left(x\right)},\ q\left(x\right)\ nilainya\ sembarang f ( x ) = q ( x ) p ( x ) , q ( x ) n i l a i n y a s e m b a r a n g

f ( x ) = p ( x ) + q ( x ) f\left(x\right)=p\left(x\right)+q\left(x\right) f ( x ) = p ( x ) + q ( x )

f ( x ) = f u n g s i p o l i n o m f\left(x\right)=fungsi\ polinom f ( x ) = f u n g s i p o l i n o m

f ( x ) = p ( x ) q ( x ) f\left(x\right)=\frac{p\left(x\right)}{q\left(x\right)} f ( x ) = q ( x ) p ( x ) , yang disebut sebagai pembilang adalah

p ( x ) p\left(x\right) p ( x )

f ( x ) f\left(x\right) f ( x )

q ( x ) q\left(x\right) q ( x )

p ( x ) s e k a l i g u q ( x ) p\left(x\right)\ sekaligu\ q\left(x\right) p ( x ) s e k a l i g u q ( x )

p ( x ) q ( x ) \frac{p\left(x\right)}{q\left(x\right)} q ( x ) p ( x )

D a e r a h a s a l f u n g s i f ( x ) = 3 x − 6 x − 2 a d a l a h Daerah\ asal\ fungsi\ f\left(x\right)=\frac{3x-6}{x-2}adalah\ D a e r a h a s a l f u n g s i f ( x ) = x − 2 3 x − 6 a d a l a h

x ∈ R , x ≠ 2 x\in R,\ x\ne2 x ∈ R , x  = 2

x ∈ R , x ≠ 3 x\in R,\ x\ne3 x ∈ R , x  = 3

x ∈ R , x ≠ 6 x\in R,\ x\ne6 x ∈ R , x  = 6

x ∈ R , x ≠ 0 x\in R,\ x\ne0 x ∈ R , x  = 0

T i t i k p o t o n g t e r h a d a p s u m b u y d a r i f ( x ) = 2 x + 4 4 x − 2 a d a l a h Titik\ potong\ terhadap\ sumbu\ y\ dari\ f\left(x\right)=\frac{2x+4}{4x-2}\ adalah T i t i k p o t o n g t e r h a d a p s u m b u y d a r i f ( x ) = 4 x − 2 2 x + 4 a d a l a h

( 0 , − 2 ) \left(0,-2\right) ( 0 , − 2 )

( 0 , 2 ) \left(0,2\right) ( 0 , 2 )

( 2 , 0 ) \left(2,0\right) ( 2 , 0 )

( − 2 , 0 ) \left(-2,0\right) ( − 2 , 0 )

t i d a k p u n y a t i t i k p o t o n g tidak\ punya\ titik\ potong t i d a k p u n y a t i t i k p o t o n g

A s i m t o t d a t a r d a r i f ( x ) = 2 x − 3 x + 3 a d a l a h Asimtot\ datar\ dari\ f\left(x\right)=\frac{2x-3}{x+3}adalah A s i m t o t d a t a r d a r i f ( x ) = x + 3 2 x − 3 a d a l a h

t i d a k m e m p u n y a i a s i m t o t d a t a r tidak\ mempunyai\ asimtot\ datar t i d a k m e m p u n y a i a s i m t o t d a t a r

Dalam menggambar grafik fungsi rasional langkah-langkahnya adalah sebagai berikut :

menentukan titik potong terhadap sumbu x dan y

menggunakan bantuan beberapa titik

Gambarlah grafik fungsi f(x) = 1 / (x - 1)

The graph will have a vertical asymptote at x = 1.

The graph will have a hole at x = 1.

The graph will have a vertical asymptote at x = 0.

The graph will have a horizontal asymptote at x = 1.

Analisis solusi pertidaksamaan (2x - 5) / (x + 3) ≤ 0

x ∈ (-∞, -3) ∪ [5/2, ∞)

x ∈ (-∞, -3) ∪ (5/2, ∞)

Langkah yang tidak termasuk dalam menggambar grafik fungsi rasional adalah ...

menentukan titik potong terhadap sumbu x dan y

menggunakan bantuan beberapa titik

Fungsi Rasional dan Irasional

Authored by Yuliana Kartika

Mathematics

11th Grade

Used 11+ times

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

nilai x dari pembilang adalah ....

x ≠ 3

x ≠ -3

x = 3

x = -3

x = 4

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Nilai x dari penyebut pertidaksamaan rasional tersebut adalah ...

x ≠ -4

x ≠ 4

x = 4

x = -4

x = 3

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Pembilang dari pertidaksamaan rasional tersebut adalah ...

x = -1

x = 1

x = 3

x = 8

x = -8

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

HP dari pertidaksamaan rasional tersebut adalah ...

-5 < x ≤ 2

-5 < x < 2

x < -5 atau x ≥ 2

x < -5 atau x > 2

-5 ≤ x ≤ 2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Syarat numerus dari pertidaksamaan irasional tersebut adalah ...

x ≥ -3

x ≥ 9

x ≥ 3

x ≥ -3

x ≤ 3

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Salah satu syarat pertidaksamaan rasional adalah ...

Penyebut sama dengan nol

Fungsi dibawah akar harus lebih besar sama dengan nol

Fungsi dibawah akar harus kurang dari sama dengan nol

Penyebut tidak sama dengan nol

Fungsi dibawah sama dengan nol

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Syarat utama dari bentuk pertidaksamaan rasional adalah ....

Pembilang tidak boleh sama dengan nol

Penyebut sama dengan nol

Penyebut tidak boleh sama dengan nol

Pembilang sama dengan nol

Mengkuadratkan kedua ruas

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

HP dari pertidaksamaan irasional tersebut adalah ....

$x\le-1$

$x<-1$

$x\le-1\ atau\ x\ge2$

$x\ge2$

$-1\le x\le2$

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