
Unit 1 Quiz 1 Block
Authored by Dawn Williams
Mathematics
9th Grade
CCSS covered

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10 questions
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1.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Identify the number of terms in the expression 12ABC + 7AB - 3C + 9.
2
3
4
5
Answer explanation
The expression 12ABC + 7AB - 3C + 9 has four distinct terms: 12ABC, 7AB, -3C, and 9. Therefore, the correct answer is 4.
Tags
CCSS.6.EE.A.2B
2.
OPEN ENDED QUESTION
3 mins • 1 pt
Identify the coefficients of each term in the expression 7AB - 3A + 12B - 9.
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Answer explanation
In the expression 7AB - 3A + 12B - 9, the coefficients are: 7 for AB, -3 for A, 12 for B, and -9 is the constant term. Thus, the coefficients are 7, -3, 12, and -9.
Tags
CCSS.6.EE.A.2B
3.
OPEN ENDED QUESTION
3 mins • 1 pt
What is the constant in the expression -20XYZ - 4XY + 16t - 5?
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Answer explanation
In the expression -20XYZ - 4XY + 16t - 5, the constant is the term that does not contain any variables. Here, -5 is the only term without variables, making it the constant.
Tags
CCSS.6.EE.A.2B
4.
OPEN ENDED QUESTION
3 mins • 1 pt
Solve the equation: 3n - 5 = 7
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Answer explanation
To solve 3n - 5 = 7, add 5 to both sides: 3n = 12. Then, divide by 3: n = 4. The correct answer is 4, not -1.
Tags
CCSS.7.EE.B.4A
5.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Solve the equation: 2x + 4 + x - 5x = -10
x = -2
x = 7
x = -4
x = 4
Answer explanation
Combine like terms: 2x + x - 5x = -2x. The equation becomes -2x + 4 = -10. Subtract 4 from both sides: -2x = -14. Divide by -2: x = -2. Thus, the correct answer is x = -2.
Tags
CCSS.8.EE.C.7B
6.
OPEN ENDED QUESTION
3 mins • 1 pt
Solve the equation: 7 = y/5 - 2
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Answer explanation
To solve 7 = y/5 - 2, first add 2 to both sides: 9 = y/5. Then, multiply both sides by 5: y = 45. Thus, the solution is y = 45.
Tags
CCSS.7.EE.B.4A
7.
OPEN ENDED QUESTION
3 mins • 1 pt
Solve the equation: 15 = 8n - 3n + 7
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Answer explanation
Combine like terms: 15 = 5n + 7. Subtract 7 from both sides: 8 = 5n. Divide by 5: n = 8/5 or 1.6. Thus, the solution is n = 1.6.
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