Limiting & Excess Reactants 2

Balance the following equation:

__KOH + __H₃PO₄ -----> __K₃PO₄ + __H₂O

Write down this equation.

• 2, 6, 1, 3

• 1, 1, 3, 3

• 3, 1, 1, 1

• 3, 1, 1, 3

What is the molar mass of KOH ?

• 630 g

• 56.11 g

• 55.10 g

• 40.11 g

If you have 10.1 g KOH and 8.50 g H₃PO₄, how many grams of H₂O can you make?

Sig figs matter! And you have to balance the equation!

KOH + H₃PO₄ --> H₂O + K₃PO₄

• 4.69 g

• 3.24 g

• 29.2 g

• 4.24 g

4NH₃ + 5O₂ --> 4NO + 6H₂O
How many grams of NO are formed if 6.30g of ammonia react with 1.80g of oxygen? 

• 0.37g
• 0.045g
• 1.35g
• 11.1g