Random Numbers + Review

What numbers can generate?
rand()%5 + 1

• 1,2,3,4,5

• 0,1,2,3,4,5

• 1,2,3,4,5,6

• 0,1,2,3,4,5,6

To create a random number between 10 and 15 use...

• rand()%6+10

• rand()%10+5

• rand()%15

• rand()%15+10

For a 6 sided die (rolls 1,2,3,4,5,6) you should use...

• rand()%6

• rand()%5 + 1

• rand()%6 + 1

• rand()%7 + 6

What does = mean ?

• It is the assignment operator.
  It sets the variable on the left side equal to what is on the right side.

• It is the equality operator. It is used to check if both sides are equal

Answer explanation

An easy way to remember is that 1 equal sign is 1-way. It sets the left side equal to the right side. 2 equal signs are 2-way, the check if BOTH are the same.

What does == mean ?

• It is the assignment operator.
  It sets the variable on the left side equal to what is on the right side.

• It is the equality operator. It is used to check if both sides are equal

Answer explanation

An easy way to remember is that 1 equal sign is 1-way. It sets the left side equal to the right side. 2 equal signs are 2-way, the check if BOTH are the same.

Why does this code always print "Oh no, your number was 1"

• The assignment operator was used instead of the equality operator

• The conditions for the if, else if, and else statements are incorrect

• The random number was generated incorrectly

• An uninitialized variable is used

Answer explanation

random = 1 in the condition resets the variable random to 1 regardless of whatever random number was generated

This code should should run until a 1 is rolled but 2 of these errors block it from compiling
'else' without a previous 'if'
What is the issue?

• There should be NO SEMICOLONS after a while loop or if statement

• true should be capitalized in an infinite loop

• The conditions are written incorrectly

• The random numbers are generated incorrectly

Answer explanation

While most lines end in a semicolon, loops and conditions DO NOT end in a semicolon.

What values should be used for y & n in this code?
(The random numbers generated should cover ONLY the options in the if statements)

• y = 3, n = 0

• y = 2, n = 1

• y = 3, n = 1

• y = 2, n = 2

Answer explanation

There are 3 options so we should use %3.

The options start at 1 so we should use +1.