Midpoint and Distance

Find the midpoint of the line segment with endpoints (-2,0) & (9,-1).

• (1, 3)

• (3.5, -.5)

• (-.5, 3.5)

• (6, -.5)

What is the midpoint between (3, -1) and (7, -5)

• (5, -2)
• (10, -6)
• (5, -3)
• (2, -2)

What is the midpoint between (3, -1) and (8, -6)

• (11, -7)
• (-5.5, -3.5)
• (5.5, -3.5)
• (2, -2)

Find the midpoint of the segment with the endpoints:(4, 12) and (-6, 14)

• (-1, 13)
• (13, 1)
• (13, -1)
• (5, 13)

Which of the following is the correct midpoint formula given two endpoints (x₁, y₁) and (x₂, y₂)?

• 
• 
• 
• 

What is the midpoint between (-4,4) and (-2,2)?

• (3,2)
• (-3,3)
• (4,5)
• (6,7)

What is the midpoint of the segment with endpoints (1, 9) and (-3, 5)?

• (-1, 7)

• (2, 7)

• (7, -1)

• (2, 2)

The length between (3, 8) and (-2, -4) is ______?

 $d=\sqrt{\left(x_2^{ }-x_1\right)^2+\left(y_2-y_1\right)^2}$  

• √17

• 13

• 17

• 169

A(3,1) B(-2,-1) written correctly is:

• $\sqrt{\left(-2-3\right)^2\ +\ \left(-1-1\right)^2}$

• $\sqrt{\left(1-3\right)^2\ +\ \left(-1-2\right)^2}$

• $\sqrt{\left(-2-3\right)^2\ -\ \left(-1-1\right)^2}$

• $\sqrt{\left(-2-3\right)^2\ -\ \left(-1-1\right)^2}$

How is AB written in the distance formula?

• 
  $d\ =\ \sqrt{\left(5-3\right)^2\ +\ \left(0--2\right)^2}$
  

• $d\ =\ \sqrt{\left(2-5\right)^2\ +\ \left(3\ -0\right)^2}$

• $d\ =\ \sqrt{\left(5-3\right)^2\ -\ \left(0--2\right)^2}$

• $d\ =\ \sqrt{\left(4-3\right)^2\ -\ \left(2-4\right)^2}$