AP Physics C: Ampere's Law and Biot-Savart

Ampere's Law helps us

• calculate the force produced by a straight conductor when a current is run through it

• calculate the current produced by a straight conductor when a magnetic field is present

• calculate the magnetic field produced by any shape conductor when a current is run through it

• calculate the amount of resistance in a wire when current is passed through it

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When Ampere ran current through 2 parallel wires in the same direction,

• the wires attracted

• the wires repelled

• the wires flew away

• the wires exploded

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NGSS.HS-PS2-5

NGSS.HS-PS3-5

When Ampere ran current through 2 parallel wires in the opposite direction,

• the wires attracted

• the wires repelled

• the wires flew away

• the wires exploded

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NGSS.HS-PS2-5

NGSS.HS-PS3-5

Ampere's law states that B = μ₀I / 2πr. The name of the constant, μ_0, is

• Ampere's number

• Ampere's constant

• the permeability of closed space

• the permeability of free space

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μ_{0 =}

• 6.67 * 10^-11 m³/kgs²

• 6.67 * 10^-11 Tm/A

• 4π * 10^-7 m³/kgs²

• 4π * 10^-7 Tm/A

What is the magnitude of a magnetic field 3.5 cm away from straight conductor with a current of 1.8 A?

• 1.0 * 10^-5 T

• 1.5 * 10^-5 T

• 2.1 * 10^-5 T

• 2.2 * 10^-4 T

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NGSS.HS-PS2-5

NGSS.HS-PS3-5

What is the magnitude of a magnetic field in the core of a 6.2 cm solenoid with a current of 11.2 A and 480 turns?

• 0.01 T

• 0.11 T

• 0.45 T

• 0.85 T

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NGSS.HS-PS2-5

Calculate the magnitude of the force between two 18 cm long wires that are 7.0 cm apart. The first wire has 3.5 A of current passing through it while the second has 8.3 A of current passing through it.

• 3.0 x 10^-5 N

• 7.5 x 10^-5 N

• 2.1 x 10^-5 N

• 1.5 x 10^-5 N

Tags

NGSS.HS-PS2-5

NGSS.HS-PS3-5