
Alg1 Literal Equations 24-25
Authored by Michelle Wilson
Mathematics
9th Grade
CCSS covered
Used 5+ times

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10 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Answer explanation
To solve for b in the equation 5a - 2b = 15, rearrange it to isolate b: 2b = 5a - 15, then divide by 2 to get b = (5a - 15)/2. The correct answer is b = (5a - 15)/2.
Tags
CCSS.HSA.CED.A.4
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Answer explanation
To solve for l in the equation P = 2l + 2w, first subtract 2w from both sides: P - 2w = 2l. Then, divide by 2 to isolate l: l = (P - 2w) / 2. Thus, the correct answer is l = \frac{P-2w}{2}.
Tags
CCSS.HSA.CED.A.4
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Answer explanation
To solve for b in the equation A = \frac{1}{2}bh, multiply both sides by 2 to get 2A = bh. Then, divide both sides by h to isolate b, resulting in b = \frac{2A}{h}, which is the correct choice.
Tags
CCSS.HSA.CED.A.4
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Answer explanation
To solve for r in the equation C = 2πr, divide both sides by 2π. This gives r = C/(2π), which matches the correct answer choice.
Tags
CCSS.HSA.CED.A.4
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Answer explanation
To solve for C, start with F = \frac{9}{5}C + 32. Subtract 32 from both sides: F - 32 = \frac{9}{5}C. Then, multiply both sides by \frac{5}{9} to isolate C: C = \frac{5}{9}(F - 32). Thus, the correct answer is C = \frac{5}{9}(F - 32).
Tags
CCSS.HSA.CED.A.4
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Answer explanation
To solve for t in the equation d = rt, divide both sides by r. This gives t = d/r, which is the correct choice. The other options do not correctly isolate t.
Tags
CCSS.HSA.CED.A.4
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Answer explanation
To solve for x in the equation y = mx + b, isolate x by subtracting b from both sides: y - b = mx. Then, divide by m to get x = (y - b)/m, which matches the correct choice.
Tags
CCSS.HSA.CED.A.4
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