
Odd and Even Functions

Quiz
•
Mathematics
•
9th - 11th Grade
•
Easy

Alix Joseph
Used 14+ times
FREE Resource
13 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Is the graph an even, odd, or neither function
f(x) = 4x3
Even
Odd
Neither
Answer explanation
The function f(x) = 4x^3 is odd because f(-x) = -f(x). This means the graph is symmetric about the origin, confirming it is an odd function.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Is the graph an even, odd, or neither function
f(x) = x2 + 2
Even
Odd
Neither
Answer explanation
The function f(x) = x² + 2 is even because f(-x) = (-x)² + 2 = x² + 2 = f(x). An even function satisfies the condition f(-x) = f(x) for all x.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Is the graph an even, odd, or neither function?
Even
Odd
Neither
Answer explanation
The graph is an even function because it satisfies the condition f(x) = f(-x) for all x in its domain. This symmetry about the y-axis confirms that the correct choice is 'Even'.
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which one of the following functions is odd?
f(x) = 3x⁴ - 4x³
g(x) = 5x⁴ + 3x²
h(x) = 6x⁵ - x³
k(x) = x⁶ + 8x²
Answer explanation
An odd function satisfies f(-x) = -f(x). For h(x) = 6x⁵ - x³, h(-x) = -6x⁵ + x³ = -h(x). The other functions are even or neither, making h(x) the only odd function.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Even, odd, or neither?
Even
Odd
Neither
Please explain this to me.
Answer explanation
The number in question is classified as odd because it cannot be evenly divided by 2, resulting in a remainder. Therefore, the correct answer is 'Odd'.
6.
MULTIPLE CHOICE QUESTION
30 sec • 5 pts
Even
Odd
Neither
Answer explanation
The function f(x) = 4x^2 + 8 is even because f(-x) = 4(-x)^2 + 8 = 4x^2 + 8 = f(x). An even function satisfies the condition f(-x) = f(x) for all x.
7.
MULTIPLE CHOICE QUESTION
30 sec • 5 pts
Even
Odd
Neither
Answer explanation
The function f(x) = 2x^3 is classified as odd because f(-x) = -f(x). This means that the function is symmetric about the origin, confirming it is an odd function.
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