Electron Configuration in Orbital Notation

Electron Configuration in Orbital Notation

Assessment

Interactive Video

Created by

Olivia Brooks

Chemistry

6th - 10th Grade

Hard

This video tutorial by Mr. Boand covers the process of drawing electron configurations in orbital notation, specifically for sodium. It begins with an introduction to sodium's atomic number and electron count, followed by a step-by-step guide on filling the 1s, 2s, and 2p orbitals according to Hund's rule. The tutorial concludes with the completion of the 3s orbital and an explanation of quantum numbers for sodium's final electron.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main topic of this video?

Drawing electron configurations in orbital notation

Understanding molecular geometry

Drawing Lewis structures

Balancing chemical equations

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the atomic number of sodium?

12

10

13

11

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many electrons does a neutral atom of sodium have?

10

13

11

12

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which orbital is filled first when drawing the electron configuration for sodium?

3s

2p

1s

2s

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many electrons can the 1s orbital hold?

1

2

3

4

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

According to Hund's rule, how should electrons be filled in the 2p orbitals?

All in one orbital first

All in the 2s orbital first

Randomly

One in each orbital before pairing

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many electrons are in the 2s orbital of sodium?

4

1

2

3

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which orbital is filled after the 2p orbitals in sodium?

1s

2s

3p

3s

9.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the angular momentum quantum number for an s-shaped orbital?

3

2

1

0

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the spin value of the first electron in the 3s orbital of sodium?

+1

+1/2

-1/2

0

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