What does molarity measure in a chemical solution?

Exploring Molarity Calculations in Chemistry

Interactive Video
•

Amelia Wright
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Chemistry
•
9th - 12th Grade
•
Hard
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10 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The number of particles in the solution
The concentration of the solute in moles per liter
The volume of the solution in liters
The weight of the solute in grams
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which unit is used to express molarity?
Liters per mole
Particles per liter
Moles per liter
Grams per liter
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the number of moles calculated from grams?
Subtract the molar mass
Add the molar mass
Multiply by the molar mass
Divide by the molar mass
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the molarity of a solution if you have 0.613 moles of solute in 1.5 liters of solution?
0.821 M
0.204 M
0.615 M
0.409 M
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is required to convert grams of a substance to moles?
The density of the substance
The boiling point of the substance
The molar mass of the substance
The volume of the substance
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you convert milliliters to liters?
Divide by 100
Divide by 1000
Multiply by 100
Multiply by 1000
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the molarity of a glucose solution with 0.0293 moles in 0.1105 liters?
0.150 M
0.300 M
0.265 M
0.215 M
8.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in calculating molarity from a given mass of solute?
Dilute the solution
Convert mass to moles
Convert mass to volume
Measure the temperature
9.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What molarity results from 8.92 x 10^-3 moles of potassium iodide in 1.85 liters?
0.0185 M
0.0482 M
0.00892 M
0.00482 M
10.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you calculate the molarity of a solution?
Divide the moles of solute by the grams of solution
Multiply the liters of solution by the moles of solute
Divide the moles of solute by the liters of solution
Multiply the grams of solute by the liters of solution
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