Acid-Base Chemistry and pH Calculations

Acid-Base Chemistry and pH Calculations

Assessment

Interactive Video

Chemistry, Science

10th - 12th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial covers untraditional acidic cations, focusing on aluminum chloride and its hydrolysis. It explains the behavior of ions in water and introduces the relationship between Ka and Kb values for conjugate acid-base pairs. The tutorial also demonstrates how to calculate the pH of salts and compares the strengths of different ions.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why was the hydrolysis equation for aluminum chloride not written in the previous video?

It is a neutral compound.

It is not relevant to the topic.

It is a very complicated equation.

It is a very simple equation.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following ions is considered neutral?

Iron

Aluminum

Chromium

Chloride

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What characteristic do small, highly charged cations share?

They have no charge.

They are always neutral.

They act as bases.

They act as acids.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to water molecules when they surround an aluminum ion in a salt solution?

They form a hydration sphere.

They dissociate completely.

They form a crystal structure.

They become neutral.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between Ka and Kb for a conjugate acid-base pair?

Ka times Kb equals Kw.

Ka is always greater than Kb.

Ka is always less than Kb.

Ka and Kb are unrelated.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of Kw at 25-degrees Celsius?

1.0 times 10 to the minus 21

1.0 times 10 to the minus 14

1.0 times 10 to the minus 7

1.0 times 10 to the minus 10

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the Kb of an ion if you know the Ka of its conjugate acid?

Subtract Kw from the Ka of the conjugate acid.

Multiply Kw by the Ka of the conjugate acid.

Divide Kw by the Ka of the conjugate acid.

Add Kw to the Ka of the conjugate acid.

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