Solving Linear Equations and Absolute Values

Solving Linear Equations and Absolute Values

Assessment

Interactive Video

Mathematics

7th - 10th Grade

Hard

Created by

Emma Peterson

FREE Resource

The video tutorial explains how to solve equations involving two absolute values. It begins by describing the method of dropping the absolute values and considering both positive and negative scenarios. The tutorial then provides a detailed, step-by-step solution for two equations, demonstrating how to isolate the variable and solve for it. The video concludes with a brief recap of the process and encourages viewers to apply the method to similar problems.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step when you have an equation with two absolute values?

Add the absolute values together

Drop the absolute values and add a plus and minus

Divide the absolute values

Multiply the absolute values

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first equation formed after dropping the absolute values?

4w + 3 = 2w - 5

4w - 3 = 2w - 5

4w - 3 = 2w + 5

4w + 3 = 2w + 5

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why do we use plus and minus when dealing with absolute values?

To make the equation more complex

Because absolute values are always positive

To account for both positive and negative solutions

To simplify the equation

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the equation 4w + 3 = 2w - 5?

Subtract 2w from both sides

Add 2w to both sides

Divide both sides by 2

Multiply both sides by 2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of w after solving 4w + 3 = 2w - 5?

w = 8

w = -4

w = 4

w = -8

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving the equation 4w + 3 = - (2w - 5)?

Add 2w to both sides

Multiply both sides by -1

Subtract 2w from both sides

Distribute the negative sign

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of distributing the negative sign in the equation 4w + 3 = - (2w - 5)?

4w - 3 = -2w + 5

4w + 3 = -2w + 5

4w + 3 = -2w - 5

4w - 3 = -2w - 5

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