
Refleksi Geometri
Authored by Irna Nuraeni
Mathematics
11th Grade
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6 questions
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1.
MULTIPLE CHOICE QUESTION
45 sec • 1 pt
Titik 𝐴(3, −5) dicerminkan terhadap titik asal (0, 0). Koordinat bayangan titik A adalah …
A'(-3,-5)
A'(-3,5)
A'(3,5)
A'(-5,3)
Answer explanation
Untuk mencerminkan titik A(3, -5) terhadap titik asal (0, 0), kita membalikkan tanda koordinatnya. Jadi, koordinat bayangan titik A adalah (-3, 5).
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Titik 𝑃(5, − 4) dicerminkan terhadap garis 𝑦 = 𝑥. Koordinat bayangan titik 𝑃 adalah …
P'(-4,-5)
P'(-4,5)
P'(4,5)
P'(4,-5)
Answer explanation
Untuk mencerminkan titik P(5, -4) terhadap garis y=x, kita tukar koordinatnya menjadi (-4, 5). Jadi, koordinat bayangan titik P adalah (-4, 5).
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Tentukan bayangan bangun segitiga ABC dengan 𝐴(1, 2), 𝐵(3, −2) dan 𝐶(4,1) akan direfleksikan oleh 𝑀𝑦
A'(1, -2), B'(3,2) dan C'(4,-1)
A'(-1, 2), B'(3,2) dan C'(-4,1)
A'(1, -2), B'(3,-2) dan C'(4,-1)
A'(1, 2), B'(3,2) dan C'(4,1)
Answer explanation
Refleksi terhadap garis 𝑀𝑦 mengubah koordinat 𝐴(1, 2) menjadi 𝐴'(1, -2), 𝐵(3, -2) menjadi 𝐵'(3, 2), dan 𝐶(4, 1) menjadi 𝐶'(4, -1). Jadi, bayangan segitiga ABC adalah 𝐴'(1, -2), 𝐵'(3, 2), 𝐶'(4, -1).
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Jika garis 2𝑦 − 3𝑥 + 6 = 0 direfleksikan terhadap sumbu 𝑥, maka persamaan bayangan garis adalah …
3x-2y+6=0
2x+3y+6=0
2x-3y+6=0
3x+2y+6=0
Answer explanation
Untuk merefleksikan garis 2𝑦 − 3𝑥 + 6 = 0 terhadap sumbu 𝑥, kita ubah tanda koefisien 𝑦. Persamaan bayangan menjadi 2(-𝑦) − 3𝑥 + 6 = 0, atau 2𝑦 + 3𝑥 + 6 = 0. Jadi, persamaan bayangan garis adalah 2𝑦 + 3𝑥 + 6 = 0.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Jika garis 𝑥 − 2𝑦 − 3 = 0 dicerminkan terhadap sumbu Y, maka persamaan bayangannya adalah …
x-2y+3=0
x+2y+3=0
2x+2y+3=0
2x+y+3=0
Answer explanation
Untuk mencerminkan garis 𝑥 − 2𝑦 − 3 = 0 terhadap sumbu Y, kita mengganti 𝑥 dengan -𝑥. Jadi, persamaan menjadi -𝑥 - 2𝑦 - 3 = 0, atau 𝑥 + 2𝑦 + 3 = 0. Ini adalah persamaan bayangannya.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Parabola 𝑦 = 𝑥2 − 3𝑥 + 2 dicerminkan terhadap sumbu y. Tentukan persamaan bayangan parabola
y=x2+3x-2
y=3x2+3x+2
y=x2+3x+2
y=3x2+2x+2
Answer explanation
Untuk mencerminkan parabola y = x^2 - 3x + 2 terhadap sumbu y, kita mengganti x dengan -x. Jadi, persamaan bayangan menjadi y = (-x)^2 - 3(-x) + 2, yang disederhanakan menjadi y = x^2 + 3x + 2.
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