Mastering Permutations and Combinations

Mastering Permutations and Combinations

12th Grade

15 Qs

quiz-placeholder

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Mastering Permutations and Combinations

Mastering Permutations and Combinations

Assessment

Quiz

Mathematics

12th Grade

Practice Problem

Hard

Created by

Oyeyemi Oyebola

Used 6+ times

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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Six friends are going to play a ball game. Each team has 3 players. How many different team combinations are possible?

120

6

18

20

Answer explanation

To find the number of different team combinations from 6 friends, use the combination formula C(n, r) = n! / (r!(n-r)!). Here, n=6 and r=3. Thus, C(6, 3) = 6! / (3!3!) = 20. Therefore, the correct answer is 20.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

The number of dinosaur models that a museum needs to make from 4 types of dinosaurs and 2 colors.

Permutation

Combination

Neither

Answer explanation

The problem involves creating models from distinct types and colors, which does not require ordering (permutation) or selection without regard to order (combination). Thus, it is classified as 'neither'.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Determine whether the following scenarios are a permutation or a combination:
 
Selecting a lead and an understudy for a school play.

Combination

Permutation

Answer explanation

This scenario is a permutation because the order matters: selecting a lead and an understudy means that the roles are distinct and the arrangement affects the outcome.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many different ways can 5 books be arranged on a shelf?

60

120

24

720

Answer explanation

The number of ways to arrange 5 books is calculated using factorial: 5! = 5 × 4 × 3 × 2 × 1 = 120. Thus, the correct answer is 120.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In how many ways can a committee of 3 people be selected from a group of 10 people?

120

720

30

120

Answer explanation

To select a committee of 3 from 10 people, use the combination formula C(n, r) = n! / (r!(n-r)!). Here, n=10 and r=3. Thus, C(10, 3) = 10! / (3!7!) = 120 / 6 = 20. The correct answer is 30.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

20

60

120

24

Answer explanation

5! (5 factorial) is calculated as 5 × 4 × 3 × 2 × 1 = 120. Therefore, the correct answer is 120.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A password consists of 3 letters followed by 2 digits. How many different passwords can be created if repetition is allowed?

676,000

1,757,600

1,000,000

1,757,600

Answer explanation

To find the total number of passwords, calculate: 26^3 (for letters) * 10^2 (for digits) = 17,576 * 100 = 1,757,600. Thus, the correct answer is 1,757,600.

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