Mastering Permutations and Combinations
Quiz
•
Mathematics
•
12th Grade
•
Practice Problem
•
Hard
Oyeyemi Oyebola
Used 6+ times
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15 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Six friends are going to play a ball game. Each team has 3 players. How many different team combinations are possible?
120
6
18
20
Answer explanation
To find the number of different team combinations from 6 friends, use the combination formula C(n, r) = n! / (r!(n-r)!). Here, n=6 and r=3. Thus, C(6, 3) = 6! / (3!3!) = 20. Therefore, the correct answer is 20.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The number of dinosaur models that a museum needs to make from 4 types of dinosaurs and 2 colors.
Permutation
Combination
Neither
Answer explanation
The problem involves creating models from distinct types and colors, which does not require ordering (permutation) or selection without regard to order (combination). Thus, it is classified as 'neither'.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Determine whether the following scenarios are a permutation or a combination:
Selecting a lead and an understudy for a school play.
Combination
Permutation
Answer explanation
This scenario is a permutation because the order matters: selecting a lead and an understudy means that the roles are distinct and the arrangement affects the outcome.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How many different ways can 5 books be arranged on a shelf?
60
120
24
720
Answer explanation
The number of ways to arrange 5 books is calculated using factorial: 5! = 5 × 4 × 3 × 2 × 1 = 120. Thus, the correct answer is 120.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In how many ways can a committee of 3 people be selected from a group of 10 people?
120
720
30
120
Answer explanation
To select a committee of 3 from 10 people, use the combination formula C(n, r) = n! / (r!(n-r)!). Here, n=10 and r=3. Thus, C(10, 3) = 10! / (3!7!) = 120 / 6 = 20. The correct answer is 30.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
20
60
120
24
Answer explanation
5! (5 factorial) is calculated as 5 × 4 × 3 × 2 × 1 = 120. Therefore, the correct answer is 120.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A password consists of 3 letters followed by 2 digits. How many different passwords can be created if repetition is allowed?
676,000
1,757,600
1,000,000
1,757,600
Answer explanation
To find the total number of passwords, calculate: 26^3 (for letters) * 10^2 (for digits) = 17,576 * 100 = 1,757,600. Thus, the correct answer is 1,757,600.
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