CSC603 Demorgan Law and If statement

What is the correct way to write an if statement in Java?

• • if x > 10

  • then

  • {

  • System.out.println("x is greater than 10");

  • }

• • if (x > 10)

  • {

  • System.out.println("x is greater than 10");

  • }

• • if x > 10:

  • System.out.println("x is greater than 10");

• • if (x > 10)

  • System.out.println("x is greater than 10")

What will be the output of the following code?

int a = 5;

if (a == 5)

System.out.println("A is 5");

else

System.out.println("A is not 5");

• No output

• A is not 5

• A is 5

• Compilation error

What does the following if statement check?

if (x >= 0 && x <= 10)

• If x is less than 0 or greater than 10

• If x is greater than or equal to 0 and less than or equal to 10

• If x is equal to 0 or 10

• If x is not equal to 0 or 10

What will be the output of this code?
int a = 10;

if (a == 5)

System.out.println("Output 1 );

else if (a > 5)

System.out.println(" Output 2 ");

else System.out.println("Output 3");

• Output 1

• output 2

• output 3

What is the correct negation of the expression !(a || b) using De Morgan's Law?

• a && b

• !a && !b

• a || !b

• !a || !b

Using De Morgan's Law, what is the negation of the condition (x < 5) && (y >= 7)?

• • (x >= 5) || (y < 7)

• • (x > 5) || (y > 7)

• • (x < 5) || (y < 7)

• • (x >= 5) && (y < 7)

What is the result of applying De Morgan's Law to the expression

!(x > 10 && y < 20)?

• (x <= 10) || (y >= 20)

• (x < 10) && (y > 20)

• (x >= 10) || (y <= 20)

• (x <= 10) && (y >= 20)

Which of the following statements is equivalent to

!(a && b)?

• a || !b

• !a || !b

• !a && !b

• a && b

If x and y are booleans, which of the following is equivalent to !(x || y) using De Morgan's Law?

• x && y

• !x && !y

• !x || !y

• x || y