RQS - 4TH YEAR

RQS - 4TH YEAR

University

15 Qs

quiz-placeholder

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RQS - 4TH YEAR

RQS - 4TH YEAR

Assessment

Quiz

Engineering

University

Hard

Created by

ENGR. JED ALLAN CANTAL, MENG-EE, RME, REE

Used 1+ times

FREE Resource

15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 2 pts

A car battery supplies a current of 50 A to the starter motor. Find the charge passing through the starter in half a minute.

1500 C

3000 C

1800 C

2000 C

Answer explanation

To find the charge, use the formula Q = I × t. Here, I = 50 A and t = 30 seconds (half a minute). Thus, Q = 50 A × 30 s = 1500 C. Therefore, the correct answer is 1500 C.

2.

MULTIPLE CHOICE QUESTION

2 mins • 2 pts

There are 5 x 1016 electrons passing a section of a conductor in 1 minute and 20 seconds. Find the magnitude of the current.

1 mA

0.01 mA

0.1 mA

10 mA

Answer explanation

To find the current, use I = Q/t. Here, Q = 5 x 10^16 electrons x 1.6 x 10^-19 C/electron = 8 x 10^-4 C. Time = 80 s. Thus, I = 8 x 10^-4 C / 80 s = 0.01 A = 0.1 mA. Therefore, the correct answer is 0.1 mA.

3.

MULTIPLE CHOICE QUESTION

2 mins • 2 pts

A copper wire of 3 mm2 cross-sectional area carries a current of 5 A. Find the velocity of the electrons in the wire.

0.122 mm/s

0.134 mm/s

0.128 mm/s

0.142 mm/s

Answer explanation

To find the electron velocity, use the formula: v = I/(nAe), where I is current, n is electron density (approximately 8.5 x 10^28 m^-3 for copper), and e is charge of an electron (1.6 x 10^-19 C). This gives v ≈ 0.122 mm/s.

4.

MULTIPLE CHOICE QUESTION

2 mins • 3 pts

A bar magnet has a cross-section of 1 cm by 2 cm. If the flux density inside the magnet is 0.14T, find the total flux on the magnet.

Answer explanation

To find the total flux, use the formula \( \Phi = B \times A \). The area \( A = 1 \text{ cm} \times 2 \text{ cm} = 2 \text{ cm}^2 = 2 \times 10^{-4} \text{ m}^2 \). Thus, \( \Phi = 0.14 \text{ T} \times 2 \times 10^{-4} \text{ m}^2 = 28 \mu Wb \).

5.

MULTIPLE CHOICE QUESTION

2 mins • 2 pts

A flux of 13.6 mWb penetrates a coil of wire 240 mm in diameter. Find the magnitude of the magnetic flux density in Tesla if the plane of the coil is perpendicular to the field.

0.3

0.8

0.4

0.5

Answer explanation

To find the magnetic flux density (B), use the formula B = Φ/A. The area A of the coil is πr², where r = 0.12 m (240 mm diameter). Thus, A = π(0.12)² ≈ 0.0454 m². B = 13.6 mWb / 0.0454 m² ≈ 0.3 T.

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

According to the convention, the magnetic field emanates

from north pole to north pole

from north pole to south pole

from south pole to soutth pole

from south pole to north pole

Answer explanation

According to convention, the magnetic field lines are drawn from the north pole to the south pole. This means that the correct answer is 'from north pole to south pole', as it reflects the direction of magnetic field lines.

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

It is known as the magnetic constant.

Permeability

Permittivity

Resisitivity

Conductivity

Answer explanation

The magnetic constant, also known as permeability, is a measure of how a material responds to a magnetic field. It is denoted by the symbol μ and is crucial in electromagnetism, distinguishing it from permittivity, resistivity, and conductivity.

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