
Database Concepts Quiz
Authored by D Varshini
Computers
University
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20 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following is true about BCNF and 3NF?
A. BCNF and 3NF are identical in terms of their requirements.
B. Every 3NF relation is also in BCNF, but not every BCNF relation is in 3NF.
C. Every BCNF relation is also in 3NF, but not every 3NF relation is in BCNF.
D. BCNF focuses on functional dependencies, while 3NF focuses on foreign key relationships.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the primary difference between a clustered and a non-clustered index?
A. A clustered index organizes data physically on the disk, while a non-clustered index does not.
B. A non-clustered index stores the entire table data, while a clustered index only stores the indexed columns.
C. A non-clustered index organizes data physically, while a clustered index only indexes columns.
D. Both indexes organize data physically but clustered indexes can have multiple instances.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following is NOT an ACID property of a transaction?
A. Atomicity
B. Consistency
C. Integrity
D. Durability
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A deadlock occurs in a database system when:
A. A transaction is forced to rollback due to a timeout.
B. A transaction is waiting indefinitely for a lock to be released.
C. All the transactions are waiting for a signal from the CPU scheduler.
D. Two or more transactions are waiting for each other to release resources.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following constraints ensures that a column cannot have NULL values, but does not imply uniqueness?
A. UNIQUE
B. PRIMARY KEY
C. NOT NULL
D. CHECK
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What type of lock allows multiple transactions to read but prevents any write operations?
A. Exclusive Lock
B. Shared Lock
C. Read Lock
D. Deadlock
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following queries will correctly filter groups based on aggregate functions?
A. SELECT department_id, COUNT(*) FROM employees HAVING COUNT(*) > 5;
B. SELECT department_id, COUNT(*) FROM employees WHERE COUNT(*) > 5;
C. SELECT department_id, COUNT(*) FROM employees GROUP BY COUNT(*) > 5;
D. SELECT department_id, COUNT(*) FROM employees WHERE department_id HAVING COUNT(*) > 5;
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