10/7: Algebra 1: Bell Ringer

How do we solve an algebraic equation?

• We do the opposite operation on BOTH sides of the equation.

• We do the same operation on both sides of the equation.

• We do the opposite operation on only 1 side of the equation.

• We don't.

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CCSS.HSA.REI.A.1

x + 15 = 12

• x = 3

• x = 27

• x = -27

• x = -3

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CCSS.6.EE.B.7

18 = c + 4

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CCSS.6.EE.B.7

• 10

• -10

• 21

• -21

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CCSS.6.EE.B.7

Solve for x

3x = 27

• x = 24

• x = 81

• x = 9

• x = 8

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CCSS.8.EE.A.2

Solve 2x - 3 = 1 

• 3
• 2
• 1
• -2

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CCSS.7.EE.B.4A