Cable Length Optimization Problems

The video tutorial explains how to minimize the cable length needed to connect Centerville, Springfield, and Shelbyville using a Y-shaped configuration. It involves setting up the problem using coordinates, applying the Pythagorean theorem, formulating a distance function, and using calculus to find and verify the critical points that minimize the cable length.

What is the main objective of the cable company in the given problem?

• To connect Centerville to Springfield and Shelbyville with the most cable.

• To connect Centerville to only Shelbyville.

• To connect Centerville to only Springfield.

• To connect Centerville to Springfield and Shelbyville with the least cable.

Tags

CCSS.1.G.A.2

What shape is the cable configuration intended to be?

• T-shaped

• Y-shaped

• X-shaped

• L-shaped

Tags

CCSS.8.G.B.8

Which theorem is used to calculate the distances from the split point to Springfield and Shelbyville?

• Pythagorean theorem

• Theorem of relativity

• Binomial theorem

• Fundamental theorem of calculus

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CCSS.HSG.GPE.B.7

What is the expression for the distance from the split point to Springfield or Shelbyville?

• x^2 + 5

• x^2 + 25

• sqrt(x^2 + 5^2)

• sqrt(x^2 + 25)

What is the function D(x) used for in this problem?

• To calculate the area of the cable configuration

• To determine the speed of cable installation

• To represent the total cable length needed

• To find the volume of the cable

What is the purpose of finding the derivative of D(x)?

• To maximize the cable length

• To find the average cable length

• To determine the cable's weight

• To minimize the cable length

What does a positive second derivative at a critical point indicate?

• An inflection point

• A minimum point

• A maximum point

• A saddle point

What is the critical value of x that minimizes the cable length?

• x = 5

• x = 3

• x = 3/sqrt(5)

• x = 5/sqrt(3)

Tags

CCSS.8.G.B.8

What is the approximate minimum amount of cable needed?

• 18.66 units

• 17.66 units

• 16.66 units

• 15.66 units

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CCSS.8.EE.A.2

Why is the negative solution for x not considered?

• Because negative values are not allowed in this problem

• Because x represents a distance, which cannot be negative

• Because it leads to a longer cable length

• Because it is not a real number

Tags

CCSS.8.EE.A.2