Operations on irrational numbers

 $-3\sqrt{12}\cdot6\sqrt{39}$  

•  $-108\sqrt{13}$  

•  $3\sqrt{13}$  

•  $36\sqrt{13}$  

•  $108i\sqrt{13}$  

What should you multiply $\frac{6}{1-\sqrt{5}}$  by to rationalize the denominator?

• -4

•  $1-\sqrt{5}$  

•  $1+\sqrt{5}$  

•  $-\frac{\left(3-3\sqrt{5}\right)}{2}$  

• 20

• 40

• 180

 $3\sqrt{8}\cdot4\sqrt{5}$  

• 
  

   $12\sqrt{40}$  
  

•  $12\sqrt{13}$  
  

•  $7\sqrt{13}$  
  

•  $24\sqrt{10}$  

Simplify: (2√25)/√5

• 2√5
• 5√2
• 2√10
• 2

• 12

Simplify:

  $6\sqrt{2}\cdot5\sqrt{14}$   

•  $32\sqrt{7}$  

•  $60\sqrt{7}$  

•  $2\sqrt{7}$  

•  $30\sqrt{7}$  

Multiply the above radicals. Write your answer in simplest form.

• 
• 
• 
• 

The number obtained on rationalizing the denominator of  $\frac{3}{\sqrt{3}}$  is

• 3

•  $\frac{\sqrt{3}}{3}$  

•  $\sqrt{3}$  

•  $3\sqrt{3}$  

 $PRODUCT\ of\ \sqrt{2}\ and\ \sqrt{18}$  

• Rational

• Irrational