Solving multi-step problems using quadratic equations in one variable

Solve the quadratic equation.
(x + 2)(x - 4) = 0

(Separate your answers with a comma. Enter the smaller answer first! Example: -2, 4)

Tags

CCSS.HSA-REI.B.4B

Solve.

x² + x - 2 = 0

• x = -1 or x = 2

• x = 0 or x = -2

• x = 1 or x = 2

• x = 1 or x = -2

Tags

CCSS.HSA-REI.B.4B

Find the zeros of this quadratic. (Solutions)

Hint: Set each factor equal to zero, then solve.

• b=4/5, b=3

• b=4, b=-3

• b=1/5, b=3

• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

Solve by factoring. 2x² = 3x

• x = 3/2

• x = 0 and x = 3/2

• x = 0

• x = 2/3

Tags

CCSS.HSA-REI.B.4B

Tags

CCSS.HSA-REI.B.4B

Find the roots of this equation
x² + x - 6 = 0

• 4, -1
• 3, -2
• -6, 1
• 2, -3

Tags

CCSS.HSA-REI.B.4B

Solve the equation by factoring:

(k+5)(k+4) = 0

• {-4, 7}

• {4, -7/3}

• {-5, -4}

• {4, 5}

Tags

CCSS.HSA-REI.B.4B

Set the following to equal zero.
a² - 7a = 20 - 6a

• a² - a - 20 = 0
• a² + a - 20 = 0
• a² -13a - 20 = 0
• a² - 13a + 20 = 0

Tags

CCSS.HSA-REI.B.4B

What characteristics are an indicator that the factoring method could be used to solve the quadratic?

Select all that apply.

• b=0 so the bx term is not in the equation

• there is a perfect square trinomial given

• a=1, b is even, and there's a non-zero number on the other side

• the expression can be easily factored

Tags

CCSS.HSA-REI.B.4B

Solve: x²-4x=21

• {-7, 3}
• {-3, 7}
• {3, 7}
• {-3,-7}

Tags

CCSS.HSA-REI.B.4B