Write the equation of the quadratic in standard form given the following:
axis of symmetry: x=1
Points: (2, 5) (-2, 21)

• f(x)=(x-1)²+5
• f(x)=1/2(x-1)²+3
• f(x)=2(x-1)²+3
• f(x)=2(x-1)²-3

• y = x² + 4x
• y = -x² - 4x
• y = -x(x + 4)
• y = -(x + 2)² + 4

A function that can be written in the form f(x)=ax²+bx+c

The standard form of a quadratic function is

• ax² + bx + c

• a(x - h)² + k

• y - y₁ = m(x - x₁)

• Ax + By = C

Find equation of quadratic function that has a vertex of (0, 0)

and is passing through the points (-5, 25) and (5, 25).

• y = x² - 5x + 25

• y = -x²

• y = x² + 5x + 25

• y = x²

• Factored

• Standard

• Vertex

Write the equation for the parabola with a vertex of (-5, 2) and passes through (-6, -1)

• $y=\left(x+5\right)^2+2$

• $y=-\left(x+5\right)^2+2$

• $y=3\left(x+5\right)^2+2$

• $y=-3\left(x+5\right)^2+2$

• $y=-3\left(x-5\right)^2+2$

Write the equation in standard form of the parabola passing through the points (1, -1), (2, -5), (3, -7).

• $y=x^2-7x+5$

• $y=-x^2+4x-7$

• $y=x^2-5x-2$

• $y=-x^2+3x-8$