Applying and analysing exponential and logarithmic functions

Find x: log₅(x) = 0

• No Solution

• x = 0

• x = 5

• x = 1

Write 2³= 8 in logarithmic form.

(Your answer should start with log.)

Mathematical Equivalence

ON

Convert 2^x+6=10 to logarithmic form

• log₄(x)=2
• log₂(4)=x
• log₂(10)=6
• log₂(x)=4

Converting exponential to logarithmic form: Convert the exponential equation 5^2 = 25 to logarithmic form

• log2(25) = 5

• log5(2) = 25

• log25(5) = 2

• log5(25) = 2

Rewrite in log form:  $8^{-3}=\frac{1}{512}$  

•  $\log_8-3=\frac{1}{512}$  

•  $\log_8\ \frac{1}{512}=-3$  

•  $\log_{-3}8=\frac{1}{512}$  

•  $\log_{\frac{1}{512}}8=-3$  

Solve for X

 $\log x=-2$  

•  $x=\frac{1}{100}$  

•  $x=10$  

•  $x=\frac{1}{10}$  

•  $x=1$  

Solve the equation for x:

 $\log\left(2x+10\right)=3$  

• 10

• 990

• 495

• -3.5

log₄1 =

• 0

• 1

• 4

• does not exist

Rewrite from logarithmic form to exponential $\ln1.349=0.3$  

•  $e^{0.3}=1.349$  

•  $e^{1.349}=0.3$  

•  $\log_{1.349}=0.3$  

•  $\log_e0.3=1.349$