Applying and analysing quadratic functions

Applying and analysing quadratic functions

9th - 12th Grade

20 Qs

quiz-placeholder

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Applying and analysing quadratic functions

Applying and analysing quadratic functions

Assessment

Quiz

Mathematics

9th - 12th Grade

Hard

CCSS
HSA-SSE.B.3B, HSF-IF.C.8A

Standards-aligned

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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

10. What are the positive and negative intervals of: x22x 4-x^2-2x\ -4 

Positive:  (, ) or All Real Numbers\left(-\infty,\ \infty\right)\ or\ All\ Real\ Numbers  

Negative: Never!Never!  

Positive:  (, ) or All Real Numbers\left(-\infty,\ \infty\right)\ or\ All\ Real\ Numbers  



Negative: (1, 3)\left(-1,\ -3\right)  

Positive:  Never!Never!   

Negative:  (, ) or All Real Numbers\left(-\infty,\ \infty\right)\ or\ All\ Real\ Numbers  

Positive:  Never!Never!  



Negative: (1, 3)\left(-1,\ -3\right)   

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Find the equation of the quadratic function with the given zeros: (2,4)

x2-6x-8
x2+6x-8
x2-6x+8
x2+6x+8

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

What factors represent the following graph?

(x - 8) (x +1)

(x - 4) (x - 2)

(x - 8) (x + 1)

(x + 4) ( x + 2)

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Numbers = 4, -4

What is the product and the sum?

Sum = 0

Product = -16

Sum = 8

Product = 16

Sum = -8

Product = -16

Sum = 0

Product = 16

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Match the following

4A 3B 1C 2D

3A 1B 2C 4D

1A 2B 3C 4D

4A 3B 2C 1D

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Which statement about f(x) = 3x2 – 10x – 8 is true?

The zeros are 2/3 and 4, because f(x) = (3x – 2)(x – 4).

The zeros are 2/3 and -4, because f(x) = (3x + 2)(x – 4).

The zeros are 2/3 and -4, because f(x) = (3x – 2)(x + 4).

The zeros are -2/3 and 4, because f(x) = (3x + 2)(x – 4).

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

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