sin𝑎c𝑜𝑠𝑏−sinbcos𝑎

tan ⁡ ( x + π 2 ) = ? \tan\left(x+\frac{π}{2}\right)=? tan ( x + 2 π ) = ?

− cot ⁡ x -\cot x − cot x

− tan ⁡ x -\tan x − tan x

sin ⁡ ( m + n ) = ? \sin\left(m+n\right)=? sin ( m + n ) = ?

sin ⁡ m cos ⁡ n + cos ⁡ m sin ⁡ n \sin m\cos n+\cos m\sin n sin m cos n + cos m sin n

sin ⁡ m cos ⁡ n + cos ⁡ n sin ⁡ m \sin m\cos n+\cos n\sin m sin m cos n + cos n sin m

sin ⁡ n cos ⁡ m − sin ⁡ m cos ⁡ n \sin n\cos m-\sin m\cos n sin n cos m − sin m cos n

cos ⁡ m cos ⁡ n − sin ⁡ m sin ⁡ n \cos m\cos n-\sin m\sin n cos m cos n − sin m sin n

cos ⁡ ( x + y ) = ? \cos\left(x+y\right)=? cos ( x + y ) = ?

cos ⁡ x cos ⁡ y − sin ⁡ x sin ⁡ y \cos x\cos y-\sin x\sin y cos x cos y − sin x sin y

cos ⁡ x cos ⁡ y + sin ⁡ x sin ⁡ y \cos x\cos y+\sin x\sin y cos x cos y + sin x sin y

sin ⁡ x cos ⁡ y − cos ⁡ y sin ⁡ x \sin x\cos y-\cos y\sin x sin x cos y − cos y sin x

sin ⁡ x cos ⁡ y + cos ⁡ x sin ⁡ y \sin x\cos y+\cos x\sin y sin x cos y + cos x sin y

tan ⁡ ( x + π 8 ) = ? \tan\left(x+\frac{π}{8}\right)=? tan ( x + 8 π ) = ?

tan ⁡ x + tan ⁡ π 8 1 − tan ⁡ x tan ⁡ π 8 \frac{\tan x+\tan\frac{π}{8}}{1-\tan x\tan\frac{π}{8}} 1 − tan x tan 8 π tan x + tan 8 π

tan ⁡ x + tan ⁡ π 8 1 + tan ⁡ x tan ⁡ π 8 \ \frac{\tan x+\tan\frac{π}{8}}{1+\tan x\tan\frac{π}{8}} 1 + tan x tan 8 π tan x + tan 8 π

tan ⁡ x − tan ⁡ π 8 1 − tan ⁡ x tan ⁡ π 8 \frac{\tan x-\tan\frac{π}{8}}{1-\tan x\tan\frac{π}{8}} 1 − tan x tan 8 π tan x − tan 8 π

tan ⁡ x − tan ⁡ π 8 1 + tan ⁡ x tan ⁡ π 8 \frac{\tan x-\tan\frac{π}{8}}{1+\tan x\tan\frac{π}{8}} 1 + tan x tan 8 π tan x − tan 8 π

cos ⁡ ( 15 ° − 48 ° ) = ? \cos\left(15\degree-48\degree\right)=? cos ( 1 5 ° − 4 8 ° ) = ?

cos ⁡ 15 ° cos ⁡ 48 ° + sin ⁡ 15 ° sin ⁡ 48 ° \cos15\degree\cos48\degree+\sin15\degree\sin48\degree cos 1 5 ° cos 4 8 ° + sin 1 5 ° sin 4 8 °

cos ⁡ 15 ° cos ⁡ 48 ° − sin ⁡ 15 ° sin ⁡ 48 ° \cos15\degree\cos48\degree-\sin15\degree\sin48\degree cos 1 5 ° cos 4 8 ° − sin 1 5 ° sin 4 8 °

cos ⁡ 15 ° cos ⁡ 48 ° + sin ⁡ 15 ° cos ⁡ 48 ° \cos15\degree\cos48\degree+\sin15\degree\cos48\degree cos 1 5 ° cos 4 8 ° + sin 1 5 ° cos 4 8 °

sin ⁡ 15 ° cos ⁡ 48 ° − cos ⁡ 15 ° sin ⁡ 48 ° \sin15\degree\cos48\degree-\cos15\degree\sin48\degree sin 1 5 ° cos 4 8 ° − cos 1 5 ° sin 4 8 °

sin ⁡ ( a + a ) = ? \sin\left(a+a\right)=? sin ( a + a ) = ?

sin ⁡ a cos ⁡ a + cos ⁡ a sin ⁡ a \sin a\cos a+\cos a\sin a sin a cos a + cos a sin a

cos ⁡ a sin ⁡ a − sin ⁡ a cos ⁡ a \cos a\sin a-\sin a\cos a cos a sin a − sin a cos a

cos ⁡ a cos ⁡ a + sin ⁡ a sin ⁡ a \cos a\cos a+\sin a\sin a cos a cos a + sin a sin a

cos ⁡ a cos ⁡ a − sin ⁡ a sin ⁡ a \cos a\cos a-\sin a\sin a cos a cos a − sin a sin a

cos ⁡ ( a + a ) = ? \cos\left(a+a\right)=? cos ( a + a ) = ?

cos ⁡ a cos ⁡ a − sin ⁡ a sin ⁡ a \cos a\cos a-\sin a\sin a cos a cos a − sin a sin a

cos ⁡ a cos ⁡ a + sin ⁡ a sin ⁡ a \cos a\cos a+\sin a\sin a cos a cos a + sin a sin a

sin ⁡ a cos ⁡ a + cos ⁡ a sin ⁡ a \sin a\cos a+\cos a\sin a sin a cos a + cos a sin a

sin ⁡ a cos ⁡ a − cos ⁡ a sin ⁡ a \sin a\cos a-\cos a\sin a sin a cos a − cos a sin a

sin ⁡ ( π 2 − x ) = ? \sin\left(\frac{π}{2}-x\right)=? sin ( 2 π − x ) = ?

− sin ⁡ x -\sin x − sin x

− cos ⁡ x -\cos x − cos x

tan ⁡ ( 165 ° ) = ? \tan\left(165\degree\right)=? tan ( 1 6 5 ° ) = ?

− tan ⁡ 15 ° -\tan15\degree − tan 1 5 °

tan ⁡ 15 ° \tan15\degree tan 1 5 °

cot ⁡ 15 ° \cot15\degree cot 1 5 °

− cot ⁡ 15 ° -\cot15\degree − cot 1 5 °

Biểu thức nào sau đâu đúng?

S i n ( a + b ) S i n ( a − b ) = T a n a + T a n b T a n a − T a n b \frac{Sin\left(a+b\right)}{Sin\left(a-b\right)}=\frac{Tana+Tanb}{Tana-Tanb} S i n ( a − b ) S i n ( a + b ) = T a n a − T a n b T a n a + T a n b

S i n ( a + b ) S i n ( a − b ) = S i n a + S i n b S i n a − S i n b \frac{Sin\left(a+b\right)}{Sin\left(a-b\right)}=\frac{Sina+Sinb}{Sina-Sinb} S i n ( a − b ) S i n ( a + b ) = S i n a − S i n b S i n a + S i n b

S i n ( a + b ) S i n ( a − b ) = S i n a − S i n b S i n a + S i n b \frac{Sin\left(a+b\right)}{Sin\left(a-b\right)}=\frac{Sina-Sinb}{Sina+Sinb} S i n ( a − b ) S i n ( a + b ) = S i n a + S i n b S i n a − S i n b

S i n ( a + b ) S i n ( a − b ) = C o t a + C o t b C o t a − C o t b \frac{Sin\left(a+b\right)}{Sin\left(a-b\right)}=\frac{Cota+Cotb}{Cota-Cotb} S i n ( a − b ) S i n ( a + b ) = C o t a − C o t b C o t a + C o t b

Đẳng thức nào sau đây đúng

C o s ( α + π 3 ) = 1 2 C o s α − 3 2 S i n α Cos\left(\alpha+\frac{\pi}{3}\right)=\frac{1}{2}Cos\alpha-\frac{\sqrt{3}}{2}Sin\alpha C o s ( α + 3 π ) = 2 1 C o s α − 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> S i n α

C o s ( α + π 3 ) = C o s α + 1 2 Cos\left(\alpha+\frac{\pi}{3}\right)=Cos\alpha+\frac{1}{2} C o s ( α + 3 π ) = C o s α + 2 1

C o s ( α + π 3 ) = 3 2 S i n α − 1 2 C o s α Cos\left(\alpha+\frac{\pi}{3}\right)=\frac{\sqrt{3}}{2}Sin\alpha-\frac{1}{2}Cos\alpha C o s ( α + 3 π ) = 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> S i n α − 2 1 C o s α

C o s ( α + π 3 ) = 1 2 S i n α − 3 2 C o s α Cos\left(\alpha+\frac{\pi}{3}\right)=\frac{1}{2}Sin\alpha-\frac{\sqrt{3}}{2}Cos\alpha C o s ( α + 3 π ) = 2 1 S i n α − 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> C o s α

A = C o s 5 4 o . C o s 4 o − C o s 3 6 o . C o s 8 6 o = ? A=\ Cos54^o.Cos4^o-Cos36^o.Cos86^o=? A = C o s 5 4 o . C o s 4 o − C o s 3 6 o . C o s 8 6 o = ?

C o s 5 8 o Cos58^o C o s 5 8 o

C o s 5 0 o Cos50^o C o s 5 0 o

S i n 5 0 o Sin50^o S i n 5 0 o

S i n 5 8 o Sin58^o S i n 5 8 o

G ọ i M , m l a ^ ˋ n l ư ợ t l a ˋ G T L N , G T N N c ủ a Gọi\ M,\ m\ lần\ lượt\ là\ GTLN,\ GTNN\ của\ G ọ i M , m l a ^ ˋ n l ư ợ t l a ˋ G T L N , G T N N c ủ a c ủ a ( 3 sin ⁡ x + 4 cos ⁡ x ) k h i đ o ˊ của\ \left(3\sin x+4\cos x\right)khi\ đó c ủ a ( 3 sin x + 4 cos x ) k h i đ o ˊ

M = 5 , m = − 5 M=5,\ m=-5 M = 5 , m = − 5

M = 4 , m = 3 M=4,\ m=3 M = 4 , m = 3

M = 3 , m = − 3 M=3,\ m=-3 M = 3 , m = − 3

M = 4 , m = − 4 M=4,\ m=-4 M = 4 , m = − 4

sin ⁡ ( π 2 − x ) = ? \sin\left(\frac{π}{2}-x\right)=? sin ( 2 π − x ) = ?

− sin ⁡ x -\sin x − sin x

− cos ⁡ x -\cos x − cos x

cos ⁡ ( x + y ) = ? \cos\left(x+y\right)=? cos ( x + y ) = ?

cos ⁡ x cos ⁡ y − sin ⁡ x sin ⁡ y \cos x\cos y-\sin x\sin y cos x cos y − sin x sin y

cos ⁡ x cos ⁡ y + sin ⁡ x sin ⁡ y \cos x\cos y+\sin x\sin y cos x cos y + sin x sin y

sin ⁡ x cos ⁡ y − cos ⁡ y sin ⁡ x \sin x\cos y-\cos y\sin x sin x cos y − cos y sin x

sin ⁡ x cos ⁡ y + cos ⁡ x sin ⁡ y \sin x\cos y+\cos x\sin y sin x cos y + cos x sin y

Điền vào chỗ chấm một đáp án thích hợp để được công thức đúng: cos ⁡ a cos ⁡ b = . . . . . . . . . . . . . \cos\ a\ \cos\ b\ =............. cos a cos b = . . . . . . . . . . . . .

1 2 ( cos ⁡ ( a − b ) + cos ⁡ ( a + b ) ) \frac{1}{2}\left(\cos\ \left(a\ -b\right)+\cos\left(a+b\right)\right) 2 1 ( cos ( a − b ) + cos ( a + b ) )

1 2 ( sin ⁡ ( a − b ) + sin ⁡ ( a + b ) ) \frac{1}{2}\left(\sin\left(a\ -b\right)+\sin\left(a+b\right)\right) 2 1 ( sin ( a − b ) + sin ( a + b ) )

cos ⁡ ( a − b ) − cos ⁡ ( a + b ) \cos\left(a\ -b\right)-\cos\left(a+b\right) cos ( a − b ) − cos ( a + b )

sin ⁡ ( a − b ) − sin ⁡ ( a + b ) \sin\left(a\ -b\right)-\sin\left(a+b\right) sin ( a − b ) − sin ( a + b )

Công thức nào sau đây SAI?

sin ⁡ a − sin ⁡ b = − 2. cos ⁡ a + b 2 . sin ⁡ a − b 2 \sin a-\sin b=-2.\cos\frac{a+b}{2}.\sin\frac{a-b}{2} sin a − sin b = − 2 . cos 2 a + b . sin 2 a − b

cos ⁡ a + cos ⁡ b = 2. cos ⁡ a + b 2 . cos ⁡ a − b 2 \cos a+\cos b=2.\cos\frac{a+b}{2}.\cos\frac{a-b}{2} cos a + cos b = 2 . cos 2 a + b . cos 2 a − b

cos ⁡ a − cos ⁡ b = − 2. sin ⁡ a + b 2 . sin ⁡ a − b 2 \cos a-\cos b=-2.\sin\frac{a+b}{2}.\sin\frac{a-b}{2} cos a − cos b = − 2 . sin 2 a + b . sin 2 a − b

sin ⁡ a + sin ⁡ b = 2. sin ⁡ a + b 2 . cos ⁡ a − b 2 \sin a+\sin b=2.\sin\frac{a+b}{2}.\cos\frac{a-b}{2} sin a + sin b = 2 . sin 2 a + b . cos 2 a − b

Điền vào chỗ chấm một đáp án thích hợp để được công thức đúng: sin ⁡ a cos ⁡ b = . . . . . . . . . . . . . \sin\ a\ \cos\ b\ =............. sin a cos b = . . . . . . . . . . . . .

1 2 ( sin ⁡ ( a − b ) + sin ⁡ ( a + b ) ) \frac{1}{2}\left(\sin\left(a\ -b\right)+\sin\left(a+b\right)\right) 2 1 ( sin ( a − b ) + sin ( a + b ) )

1 2 ( cos ⁡ ( a − b ) + cos ⁡ ( a + b ) ) \frac{1}{2}\left(\cos\ \left(a\ -b\right)+\cos\left(a+b\right)\right) 2 1 ( cos ( a − b ) + cos ( a + b ) )

1 2 ( cos ⁡ ( a − b ) − cos ⁡ ( a + b ) ) \frac{1}{2}\left(\cos\left(a\ -b\right)-\cos\left(a+b\right)\right) 2 1 ( cos ( a − b ) − cos ( a + b ) )

1 2 ( sin ⁡ ( a − b ) − sin ⁡ ( a + b ) ) \frac{1}{2}\left(\sin\left(a\ -b\right)-\sin\left(a+b\right)\right) 2 1 ( sin ( a − b ) − sin ( a + b ) )

Biến đổi thành tích : cos ⁡ 3 x + cos ⁡ x \cos3x+\cos x cos 3 x + cos x

2 cos ⁡ 2 x . cos ⁡ x 2\cos2x.\cos x 2 cos 2 x . cos x

2 cos ⁡ 4 x . cos ⁡ x 2\cos4x.\cos x 2 cos 4 x . cos x

2 cos ⁡ 4 x . cos ⁡ 2 x 2\cos4x.\cos2x 2 cos 4 x . cos 2 x

2 cos ⁡ 4 x . sin ⁡ x 2\cos4x.\sin x 2 cos 4 x . sin x

Biến đổi thành tích : cos ⁡ 3 x − cos ⁡ x \cos3x-\cos x cos 3 x − cos x

− 2 sin ⁡ 2 x . sin ⁡ x -2\sin2x.\sin x − 2 sin 2 x . sin x

− 2 sin ⁡ 4 x . sin ⁡ x -2\sin4x.\sin x − 2 sin 4 x . sin x

− 2 sin ⁡ 3 x . sin ⁡ x -2\sin3x.\sin x − 2 sin 3 x . sin x

− 2 sin ⁡ 4 x . sin ⁡ 2 x -2\sin4x.\sin2x − 2 sin 4 x . sin 2 x

Biến đổi thành tích : sin ⁡ 5 x − sin ⁡ 3 x \sin5x-\sin3x sin 5 x − sin 3 x

2 cos ⁡ 4 x . sin ⁡ x 2\cos4x.\sin x 2 cos 4 x . sin x

− 2 cos ⁡ 4 x . sin ⁡ x -2\cos4x.\sin x − 2 cos 4 x . sin x

2 cos ⁡ 8 x . sin ⁡ x 2\cos8x.\sin x 2 cos 8 x . sin x

2 cos ⁡ 8 x . sin ⁡ 2 x 2\cos8x.\sin2x 2 cos 8 x . sin 2 x

sin ⁡ 4 x b a ˘ ˋ n g \sin4x\ bằng sin 4 x b a ˘ ˋ n g

2 sin ⁡ 2 x . cos ⁡ 2 x 2\sin2x.\cos2x 2 sin 2 x . cos 2 x

2 sin ⁡ 4 x . cos ⁡ 4 x 2\sin4x.\cos4x 2 sin 4 x . cos 4 x

2 sin ⁡ x . cos ⁡ x 2\sin x.\cos x 2 sin x . cos x

2 cos ⁡ 8 x . sin ⁡ 8 x 2\cos8x.\sin8x 2 cos 8 x . sin 8 x

1 2 sin ⁡ 3 x + 3 2 cos ⁡ 3 x b a ˘ ˋ n g \frac{1}{2}\sin3x+\frac{\sqrt{3}}{2}\cos3x\ bằng 2 1 sin 3 x + 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> cos 3 x b a ˘ ˋ n g

sin ⁡ ( 3 x + π 3 ) \sin\left(3x+\frac{\pi}{3}\right) sin ( 3 x + 3 π )

sin ⁡ ( 3 x − π 3 ) \sin\left(3x-\frac{\pi}{3}\right) sin ( 3 x − 3 π )

cos ⁡ ( 3 x + π 3 ) \cos\left(3x+\frac{\pi}{3}\right) cos ( 3 x + 3 π )

cos ⁡ ( 3 x − π 3 ) \cos\left(3x-\frac{\pi}{3}\right) cos ( 3 x − 3 π )

sin ⁡ ( π 2 − 3 a ) = . . . . \sin\left(\frac{\pi}{2}-3a\right)=.... sin ( 2 π − 3 a ) = . . . .

− cos ⁡ 3 a -\cos3a − cos 3 a

− sin ⁡ 3 a -\sin3a − sin 3 a

D = cos ⁡ ( a + b ) cos ⁡ ( a − b ) D=\cos\left(a+b\right)\cos\left(a-b\right) D = cos ( a + b ) cos ( a − b ) Cho hai góc nhọn a và b, biết cos a = 1/3; cos b = 1/4. Tính giá trị biểu thức D.

− 119 144 \frac{-119}{144} 1 4 4 − 1 1 9

− 113 144 \frac{-113}{144} 1 4 4 − 1 1 3

− 115 144 \frac{-115}{144} 1 4 4 − 1 1 5

− 117 144 \frac{-117}{144} 1 4 4 − 1 1 7

Biến đổi lượng giác

Authored by Phuong Thao

Mathematics, Chemistry

11th Grade

Used 6+ times

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MULTIPLE CHOICE QUESTION

1 min • 1 pt

Trong các mệnh đề sau, mệnh đề nào đúng?

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Trong các công thức sau, công thức nào sai?

MULTIPLE SELECT QUESTION

1 min • 1 pt

Trong các công thức sau, công thức nào đúng? (có thể lựa chọn nhiều đáp án)

FILL IN THE BLANKS QUESTION

1 min • 1 pt

Hoàn thành công thức sau: (câu trả lời cách sau bằng dấu "/")
$\cos a+\cos b=2...\left(\frac{a+b}{2}\right)...\left(\frac{a-b}{2}\right)$

(a)

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Công thức sau đúng hay sai?
$\cos^2x=\frac{1-\cos2x}{2}$

Đúng

Sai

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Công thức sau đúng hay sai?
$\sin^2x=\frac{\cos2x-1}{2}$

Đúng

Sai

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Trong các công thức dưới đây, công thức nào SAI?

FILL IN THE BLANKS QUESTION

1 min • 1 pt

Hoàn thành công thức sau:
$\cos2x=1-2\left(...x\right)^2$

(a)

10.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Mệnh đề nào sau đây đúng?

cos2a= $1-2\sin^2a$

cos2a= $\sin^2a-\cos^2a$

cos2a= $\cos^2a-1$

cos2a= $1-2\cos^2a$

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Biến đổi lượng giác

Trong các mệnh đề sau, mệnh đề nào đúng?

Trong các công thức sau, công thức nào sai?

Trong các công thức sau, công thức nào đúng? (có thể lựa chọn nhiều đáp án)

Hoàn thành công thức sau: (câu trả lời cách sau bằng dấu "/") cos⁡a+cos⁡b=2...(a+b2)...(a−b2)\cos a+\cos b=2...\left(\frac{a+b}{2}\right)...\left(\frac{a-b}{2}\right)cosa+cosb=2...(2a+b​)...(2a−b​) (a)

Công thức sau đúng hay sai? cos⁡2x=1−cos⁡2x2\cos^2x=\frac{1-\cos2x}{2}cos2x=21−cos2x​

Công thức sau đúng hay sai? sin⁡2x=cos⁡2x−12\sin^2x=\frac{\cos2x-1}{2}sin2x=2cos2x−1​

Trong các công thức dưới đây, công thức nào SAI?

Hoàn thành công thức sau: cos⁡2x=1−2(...x)2\cos2x=1-2\left(...x\right)^2cos2x=1−2(...x)2 (a)

Trong các công thức sau, công thức nào là công thức đúng? (có thể chọn nhiều đáp án)

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Hoàn thành công thức sau: (câu trả lời cách sau bằng dấu "/")
$\cos a+\cos b=2...\left(\frac{a+b}{2}\right)...\left(\frac{a-b}{2}\right)$

(a)

Công thức sau đúng hay sai?
$\cos^2x=\frac{1-\cos2x}{2}$

Công thức sau đúng hay sai?
$\sin^2x=\frac{\cos2x-1}{2}$

Hoàn thành công thức sau:
$\cos2x=1-2\left(...x\right)^2$

(a)