sin𝑎c𝑜𝑠𝑏−sinbcos𝑎

tan ⁡ ( x + π 2 ) = ? \tan\left(x+\frac{π}{2}\right)=? tan ( x + 2 π ) = ?

− cot ⁡ x -\cot x − cot x

− tan ⁡ x -\tan x − tan x

sin ⁡ ( m + n ) = ? \sin\left(m+n\right)=? sin ( m + n ) = ?

sin ⁡ m cos ⁡ n + cos ⁡ m sin ⁡ n \sin m\cos n+\cos m\sin n sin m cos n + cos m sin n

sin ⁡ m cos ⁡ n + cos ⁡ n sin ⁡ m \sin m\cos n+\cos n\sin m sin m cos n + cos n sin m

sin ⁡ n cos ⁡ m − sin ⁡ m cos ⁡ n \sin n\cos m-\sin m\cos n sin n cos m − sin m cos n

cos ⁡ m cos ⁡ n − sin ⁡ m sin ⁡ n \cos m\cos n-\sin m\sin n cos m cos n − sin m sin n

cos ⁡ ( x + y ) = ? \cos\left(x+y\right)=? cos ( x + y ) = ?

cos ⁡ x cos ⁡ y − sin ⁡ x sin ⁡ y \cos x\cos y-\sin x\sin y cos x cos y − sin x sin y

cos ⁡ x cos ⁡ y + sin ⁡ x sin ⁡ y \cos x\cos y+\sin x\sin y cos x cos y + sin x sin y

sin ⁡ x cos ⁡ y − cos ⁡ y sin ⁡ x \sin x\cos y-\cos y\sin x sin x cos y − cos y sin x

sin ⁡ x cos ⁡ y + cos ⁡ x sin ⁡ y \sin x\cos y+\cos x\sin y sin x cos y + cos x sin y

tan ⁡ ( x + π 8 ) = ? \tan\left(x+\frac{π}{8}\right)=? tan ( x + 8 π ) = ?

tan ⁡ x + tan ⁡ π 8 1 − tan ⁡ x tan ⁡ π 8 \frac{\tan x+\tan\frac{π}{8}}{1-\tan x\tan\frac{π}{8}} 1 − tan x tan 8 π tan x + tan 8 π

tan ⁡ x + tan ⁡ π 8 1 + tan ⁡ x tan ⁡ π 8 \ \frac{\tan x+\tan\frac{π}{8}}{1+\tan x\tan\frac{π}{8}} 1 + tan x tan 8 π tan x + tan 8 π

tan ⁡ x − tan ⁡ π 8 1 − tan ⁡ x tan ⁡ π 8 \frac{\tan x-\tan\frac{π}{8}}{1-\tan x\tan\frac{π}{8}} 1 − tan x tan 8 π tan x − tan 8 π

tan ⁡ x − tan ⁡ π 8 1 + tan ⁡ x tan ⁡ π 8 \frac{\tan x-\tan\frac{π}{8}}{1+\tan x\tan\frac{π}{8}} 1 + tan x tan 8 π tan x − tan 8 π

cos ⁡ ( 15 ° − 48 ° ) = ? \cos\left(15\degree-48\degree\right)=? cos ( 1 5 ° − 4 8 ° ) = ?

cos ⁡ 15 ° cos ⁡ 48 ° + sin ⁡ 15 ° sin ⁡ 48 ° \cos15\degree\cos48\degree+\sin15\degree\sin48\degree cos 1 5 ° cos 4 8 ° + sin 1 5 ° sin 4 8 °

cos ⁡ 15 ° cos ⁡ 48 ° − sin ⁡ 15 ° sin ⁡ 48 ° \cos15\degree\cos48\degree-\sin15\degree\sin48\degree cos 1 5 ° cos 4 8 ° − sin 1 5 ° sin 4 8 °

cos ⁡ 15 ° cos ⁡ 48 ° + sin ⁡ 15 ° cos ⁡ 48 ° \cos15\degree\cos48\degree+\sin15\degree\cos48\degree cos 1 5 ° cos 4 8 ° + sin 1 5 ° cos 4 8 °

sin ⁡ 15 ° cos ⁡ 48 ° − cos ⁡ 15 ° sin ⁡ 48 ° \sin15\degree\cos48\degree-\cos15\degree\sin48\degree sin 1 5 ° cos 4 8 ° − cos 1 5 ° sin 4 8 °

sin ⁡ ( a + a ) = ? \sin\left(a+a\right)=? sin ( a + a ) = ?

sin ⁡ a cos ⁡ a + cos ⁡ a sin ⁡ a \sin a\cos a+\cos a\sin a sin a cos a + cos a sin a

cos ⁡ a sin ⁡ a − sin ⁡ a cos ⁡ a \cos a\sin a-\sin a\cos a cos a sin a − sin a cos a

cos ⁡ a cos ⁡ a + sin ⁡ a sin ⁡ a \cos a\cos a+\sin a\sin a cos a cos a + sin a sin a

cos ⁡ a cos ⁡ a − sin ⁡ a sin ⁡ a \cos a\cos a-\sin a\sin a cos a cos a − sin a sin a

cos ⁡ ( a + a ) = ? \cos\left(a+a\right)=? cos ( a + a ) = ?

cos ⁡ a cos ⁡ a − sin ⁡ a sin ⁡ a \cos a\cos a-\sin a\sin a cos a cos a − sin a sin a

cos ⁡ a cos ⁡ a + sin ⁡ a sin ⁡ a \cos a\cos a+\sin a\sin a cos a cos a + sin a sin a

sin ⁡ a cos ⁡ a + cos ⁡ a sin ⁡ a \sin a\cos a+\cos a\sin a sin a cos a + cos a sin a

sin ⁡ a cos ⁡ a − cos ⁡ a sin ⁡ a \sin a\cos a-\cos a\sin a sin a cos a − cos a sin a

sin ⁡ ( π 2 − x ) = ? \sin\left(\frac{π}{2}-x\right)=? sin ( 2 π − x ) = ?

− sin ⁡ x -\sin x − sin x

− cos ⁡ x -\cos x − cos x

tan ⁡ ( 165 ° ) = ? \tan\left(165\degree\right)=? tan ( 1 6 5 ° ) = ?

− tan ⁡ 15 ° -\tan15\degree − tan 1 5 °

tan ⁡ 15 ° \tan15\degree tan 1 5 °

cot ⁡ 15 ° \cot15\degree cot 1 5 °

− cot ⁡ 15 ° -\cot15\degree − cot 1 5 °

Biểu thức nào sau đâu đúng?

S i n ( a + b ) S i n ( a − b ) = T a n a + T a n b T a n a − T a n b \frac{Sin\left(a+b\right)}{Sin\left(a-b\right)}=\frac{Tana+Tanb}{Tana-Tanb} S i n ( a − b ) S i n ( a + b ) = T a n a − T a n b T a n a + T a n b

S i n ( a + b ) S i n ( a − b ) = S i n a + S i n b S i n a − S i n b \frac{Sin\left(a+b\right)}{Sin\left(a-b\right)}=\frac{Sina+Sinb}{Sina-Sinb} S i n ( a − b ) S i n ( a + b ) = S i n a − S i n b S i n a + S i n b

S i n ( a + b ) S i n ( a − b ) = S i n a − S i n b S i n a + S i n b \frac{Sin\left(a+b\right)}{Sin\left(a-b\right)}=\frac{Sina-Sinb}{Sina+Sinb} S i n ( a − b ) S i n ( a + b ) = S i n a + S i n b S i n a − S i n b

S i n ( a + b ) S i n ( a − b ) = C o t a + C o t b C o t a − C o t b \frac{Sin\left(a+b\right)}{Sin\left(a-b\right)}=\frac{Cota+Cotb}{Cota-Cotb} S i n ( a − b ) S i n ( a + b ) = C o t a − C o t b C o t a + C o t b

Đẳng thức nào sau đây đúng

C o s ( α + π 3 ) = 1 2 C o s α − 3 2 S i n α Cos\left(\alpha+\frac{\pi}{3}\right)=\frac{1}{2}Cos\alpha-\frac{\sqrt{3}}{2}Sin\alpha C o s ( α + 3 π ) = 2 1 C o s α − 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> S i n α

C o s ( α + π 3 ) = C o s α + 1 2 Cos\left(\alpha+\frac{\pi}{3}\right)=Cos\alpha+\frac{1}{2} C o s ( α + 3 π ) = C o s α + 2 1

C o s ( α + π 3 ) = 3 2 S i n α − 1 2 C o s α Cos\left(\alpha+\frac{\pi}{3}\right)=\frac{\sqrt{3}}{2}Sin\alpha-\frac{1}{2}Cos\alpha C o s ( α + 3 π ) = 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> S i n α − 2 1 C o s α

C o s ( α + π 3 ) = 1 2 S i n α − 3 2 C o s α Cos\left(\alpha+\frac{\pi}{3}\right)=\frac{1}{2}Sin\alpha-\frac{\sqrt{3}}{2}Cos\alpha C o s ( α + 3 π ) = 2 1 S i n α − 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> C o s α

A = C o s 5 4 o . C o s 4 o − C o s 3 6 o . C o s 8 6 o = ? A=\ Cos54^o.Cos4^o-Cos36^o.Cos86^o=? A = C o s 5 4 o . C o s 4 o − C o s 3 6 o . C o s 8 6 o = ?

C o s 5 8 o Cos58^o C o s 5 8 o

C o s 5 0 o Cos50^o C o s 5 0 o

S i n 5 0 o Sin50^o S i n 5 0 o

S i n 5 8 o Sin58^o S i n 5 8 o

G ọ i M , m l a ^ ˋ n l ư ợ t l a ˋ G T L N , G T N N c ủ a Gọi\ M,\ m\ lần\ lượt\ là\ GTLN,\ GTNN\ của\ G ọ i M , m l a ^ ˋ n l ư ợ t l a ˋ G T L N , G T N N c ủ a c ủ a ( 3 sin ⁡ x + 4 cos ⁡ x ) k h i đ o ˊ của\ \left(3\sin x+4\cos x\right)khi\ đó c ủ a ( 3 sin x + 4 cos x ) k h i đ o ˊ

M = 5 , m = − 5 M=5,\ m=-5 M = 5 , m = − 5

M = 4 , m = 3 M=4,\ m=3 M = 4 , m = 3

M = 3 , m = − 3 M=3,\ m=-3 M = 3 , m = − 3

M = 4 , m = − 4 M=4,\ m=-4 M = 4 , m = − 4

sin ⁡ ( π 2 − x ) = ? \sin\left(\frac{π}{2}-x\right)=? sin ( 2 π − x ) = ?

− sin ⁡ x -\sin x − sin x

− cos ⁡ x -\cos x − cos x

cos ⁡ ( x + y ) = ? \cos\left(x+y\right)=? cos ( x + y ) = ?

cos ⁡ x cos ⁡ y − sin ⁡ x sin ⁡ y \cos x\cos y-\sin x\sin y cos x cos y − sin x sin y

cos ⁡ x cos ⁡ y + sin ⁡ x sin ⁡ y \cos x\cos y+\sin x\sin y cos x cos y + sin x sin y

sin ⁡ x cos ⁡ y − cos ⁡ y sin ⁡ x \sin x\cos y-\cos y\sin x sin x cos y − cos y sin x

sin ⁡ x cos ⁡ y + cos ⁡ x sin ⁡ y \sin x\cos y+\cos x\sin y sin x cos y + cos x sin y

Điền vào chỗ chấm một đáp án thích hợp để được công thức đúng: cos ⁡ a cos ⁡ b = . . . . . . . . . . . . . \cos\ a\ \cos\ b\ =............. cos a cos b = . . . . . . . . . . . . .

1 2 ( cos ⁡ ( a − b ) + cos ⁡ ( a + b ) ) \frac{1}{2}\left(\cos\ \left(a\ -b\right)+\cos\left(a+b\right)\right) 2 1 ( cos ( a − b ) + cos ( a + b ) )

1 2 ( sin ⁡ ( a − b ) + sin ⁡ ( a + b ) ) \frac{1}{2}\left(\sin\left(a\ -b\right)+\sin\left(a+b\right)\right) 2 1 ( sin ( a − b ) + sin ( a + b ) )

cos ⁡ ( a − b ) − cos ⁡ ( a + b ) \cos\left(a\ -b\right)-\cos\left(a+b\right) cos ( a − b ) − cos ( a + b )

sin ⁡ ( a − b ) − sin ⁡ ( a + b ) \sin\left(a\ -b\right)-\sin\left(a+b\right) sin ( a − b ) − sin ( a + b )

Công thức nào sau đây SAI?

sin ⁡ a − sin ⁡ b = − 2. cos ⁡ a + b 2 . sin ⁡ a − b 2 \sin a-\sin b=-2.\cos\frac{a+b}{2}.\sin\frac{a-b}{2} sin a − sin b = − 2 . cos 2 a + b . sin 2 a − b

cos ⁡ a + cos ⁡ b = 2. cos ⁡ a + b 2 . cos ⁡ a − b 2 \cos a+\cos b=2.\cos\frac{a+b}{2}.\cos\frac{a-b}{2} cos a + cos b = 2 . cos 2 a + b . cos 2 a − b

cos ⁡ a − cos ⁡ b = − 2. sin ⁡ a + b 2 . sin ⁡ a − b 2 \cos a-\cos b=-2.\sin\frac{a+b}{2}.\sin\frac{a-b}{2} cos a − cos b = − 2 . sin 2 a + b . sin 2 a − b

sin ⁡ a + sin ⁡ b = 2. sin ⁡ a + b 2 . cos ⁡ a − b 2 \sin a+\sin b=2.\sin\frac{a+b}{2}.\cos\frac{a-b}{2} sin a + sin b = 2 . sin 2 a + b . cos 2 a − b

Điền vào chỗ chấm một đáp án thích hợp để được công thức đúng: sin ⁡ a cos ⁡ b = . . . . . . . . . . . . . \sin\ a\ \cos\ b\ =............. sin a cos b = . . . . . . . . . . . . .

1 2 ( sin ⁡ ( a − b ) + sin ⁡ ( a + b ) ) \frac{1}{2}\left(\sin\left(a\ -b\right)+\sin\left(a+b\right)\right) 2 1 ( sin ( a − b ) + sin ( a + b ) )

1 2 ( cos ⁡ ( a − b ) + cos ⁡ ( a + b ) ) \frac{1}{2}\left(\cos\ \left(a\ -b\right)+\cos\left(a+b\right)\right) 2 1 ( cos ( a − b ) + cos ( a + b ) )

1 2 ( cos ⁡ ( a − b ) − cos ⁡ ( a + b ) ) \frac{1}{2}\left(\cos\left(a\ -b\right)-\cos\left(a+b\right)\right) 2 1 ( cos ( a − b ) − cos ( a + b ) )

1 2 ( sin ⁡ ( a − b ) − sin ⁡ ( a + b ) ) \frac{1}{2}\left(\sin\left(a\ -b\right)-\sin\left(a+b\right)\right) 2 1 ( sin ( a − b ) − sin ( a + b ) )

Biến đổi thành tích : cos ⁡ 3 x + cos ⁡ x \cos3x+\cos x cos 3 x + cos x

2 cos ⁡ 2 x . cos ⁡ x 2\cos2x.\cos x 2 cos 2 x . cos x

2 cos ⁡ 4 x . cos ⁡ x 2\cos4x.\cos x 2 cos 4 x . cos x

2 cos ⁡ 4 x . cos ⁡ 2 x 2\cos4x.\cos2x 2 cos 4 x . cos 2 x

2 cos ⁡ 4 x . sin ⁡ x 2\cos4x.\sin x 2 cos 4 x . sin x

Biến đổi thành tích : cos ⁡ 3 x − cos ⁡ x \cos3x-\cos x cos 3 x − cos x

− 2 sin ⁡ 2 x . sin ⁡ x -2\sin2x.\sin x − 2 sin 2 x . sin x

− 2 sin ⁡ 4 x . sin ⁡ x -2\sin4x.\sin x − 2 sin 4 x . sin x

− 2 sin ⁡ 3 x . sin ⁡ x -2\sin3x.\sin x − 2 sin 3 x . sin x

− 2 sin ⁡ 4 x . sin ⁡ 2 x -2\sin4x.\sin2x − 2 sin 4 x . sin 2 x

Biến đổi thành tích : sin ⁡ 5 x − sin ⁡ 3 x \sin5x-\sin3x sin 5 x − sin 3 x

2 cos ⁡ 4 x . sin ⁡ x 2\cos4x.\sin x 2 cos 4 x . sin x

− 2 cos ⁡ 4 x . sin ⁡ x -2\cos4x.\sin x − 2 cos 4 x . sin x

2 cos ⁡ 8 x . sin ⁡ x 2\cos8x.\sin x 2 cos 8 x . sin x

2 cos ⁡ 8 x . sin ⁡ 2 x 2\cos8x.\sin2x 2 cos 8 x . sin 2 x

sin ⁡ 4 x b a ˘ ˋ n g \sin4x\ bằng sin 4 x b a ˘ ˋ n g

2 sin ⁡ 2 x . cos ⁡ 2 x 2\sin2x.\cos2x 2 sin 2 x . cos 2 x

2 sin ⁡ 4 x . cos ⁡ 4 x 2\sin4x.\cos4x 2 sin 4 x . cos 4 x

2 sin ⁡ x . cos ⁡ x 2\sin x.\cos x 2 sin x . cos x

2 cos ⁡ 8 x . sin ⁡ 8 x 2\cos8x.\sin8x 2 cos 8 x . sin 8 x

1 2 sin ⁡ 3 x + 3 2 cos ⁡ 3 x b a ˘ ˋ n g \frac{1}{2}\sin3x+\frac{\sqrt{3}}{2}\cos3x\ bằng 2 1 sin 3 x + 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> cos 3 x b a ˘ ˋ n g

sin ⁡ ( 3 x + π 3 ) \sin\left(3x+\frac{\pi}{3}\right) sin ( 3 x + 3 π )

sin ⁡ ( 3 x − π 3 ) \sin\left(3x-\frac{\pi}{3}\right) sin ( 3 x − 3 π )

cos ⁡ ( 3 x + π 3 ) \cos\left(3x+\frac{\pi}{3}\right) cos ( 3 x + 3 π )

cos ⁡ ( 3 x − π 3 ) \cos\left(3x-\frac{\pi}{3}\right) cos ( 3 x − 3 π )

sin ⁡ ( π 2 − 3 a ) = . . . . \sin\left(\frac{\pi}{2}-3a\right)=.... sin ( 2 π − 3 a ) = . . . .

− cos ⁡ 3 a -\cos3a − cos 3 a

− sin ⁡ 3 a -\sin3a − sin 3 a

D = cos ⁡ ( a + b ) cos ⁡ ( a − b ) D=\cos\left(a+b\right)\cos\left(a-b\right) D = cos ( a + b ) cos ( a − b ) Cho hai góc nhọn a và b, biết cos a = 1/3; cos b = 1/4. Tính giá trị biểu thức D.

− 119 144 \frac{-119}{144} 1 4 4 − 1 1 9

− 113 144 \frac{-113}{144} 1 4 4 − 1 1 3

− 115 144 \frac{-115}{144} 1 4 4 − 1 1 5

− 117 144 \frac{-117}{144} 1 4 4 − 1 1 7

Biến đổi lượng giác

Authored by Phuong Thao

Mathematics, Chemistry

11th Grade

Used 6+ times

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