Exponential Growth and Decay

Front

Population of fish starts at 8,000 and decreases by 6% per year. What is the population after 10 years?

Back

4309

Front

Daniel’s Print Shop purchased a new printer for $35,000. Each year it depreciates at a rate of 5%. How much will the printer be worth in 8 years?

Back

$23,219.72

Front

The number of mosquitoes at the beginning of the summer was 4,000. The population of mosquitoes is expected to grow at a rate of 25% a month. How many mosquitoes will there be after 4 months?

Back

To find the number of mosquitoes after 4 months, we can use the formula: $P = P_0(1 + r)^t$, where $P_0$ is the initial population, $r$ is the growth rate, and $t$ is the time in months. Here, $P_0 = 4000$, $r = 0.25$, and $t = 4$. Thus, $P = 4000(1 + 0.25)^4 = 4000(1.25)^4 = 4000(2.44140625) \approx 9765$.

Front

Twenty years ago, Mr. Davis purchased his home for $160,000. Since then, the value of the home has increased about 5% per year. How much is the home worth today?

Back

$424,527.63

Front

Is this exponential growth or decay?

Back

Decay

Front

Initial value for the function: f(x) = 300(1.16)^x?

Back

300

Front

Exponential growth function for a painting valued at $1400 with a 9% annual increase.

Back

y=1400(1.09)^x

Front

Function with initial amount of $15 and 35% increase each year: y = 15(35)^x, y = 15(1.35)^x, y = 15(0.35)^x, y = 35(1.15)^x

Back

y = 15(1.35)^x

Front

Classify the model: A=1200(.85)⁶ as Exponential GROWTH or DECAY.

Back

Decay

Front

Classify the model: A=10(1.01)³
Options: Growth, Decay

Back

Growth