Finding Zeros of Polynomials

Find all the real zeros of the function 
f(x) = 2x³ - 19x² + 38x + 24 given that x-4 is a factor.

• x = 1/2, -6
• x = -1/2, 6
• x = 4, -1/2, 6
• x = -4, 1/2, -6

Tags

CCSS.HSA.APR.B.2

Factor:
 x³-12x²+47x-60=0 when 5 is a root.

• (x-3)(x-4)(x-5)=0
• (x+1)(x-4)(x-5)=0
• (x-3)(x-4)(2x-5)=0
• (x-5)(x-4)(x-5)=0

Tags

CCSS.HSA.APR.B.2

Find all rational zeros, one zero has been given.
f(x) = x³-3x²-x+3;   3

• 2,4,3
• -1,1,3
• 3,2,1
• 4,5,6

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

Find all rational zeros, one zero has been given.
f(x) = x³-5x²-2x+24;   -2

• -2,1,0
• -2,-3,-4
• 4,3,-2
• 0,0,0

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

Factor
x² -16x + 48

• (x - 12)(x - 4)
• (x + 6)(x - 8)
• (x + 12)(x - 4)
• (x -16)(x - 3)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

How could you determine    if x-2 is a factor of 2x³-5x²+x-2?

• Use synthetic division and see if the quotient is even
• Ask the person sitting next to me
• Use synthetic division and see if the remainder is zero
• Flip a coin

Tags

CCSS.HSA.APR.D.6

Factor f(x)= x³ - 2x²-13x - 10  given that
(x - 5) is one factor.

• (x- 5)(x - 1)(x - 2)
• (x - 5)(x + 2)(x - 2)
• (x - 5)(x + 2) (x + 1)
• (x - 5)(2x - 13)

Tags

CCSS.HSA.APR.B.2

Find all zeroes given a factor of (x+3).

f(x) = 2x³ + 5x² - 6x - 9

• -1,-3,-3

• -1,-3,3/2

• 3,3,3

• -3,2/3,-1

Tags

CCSS.HSF-IF.C.7C

Find all solutions, one factor has been given.

f(x) =x³-3x²-25x+75; (x-5)

• 5,-3,5

• 5,5,5

• 3,-5,5

• 1,1,1

Tags

CCSS.HSA.APR.B.2

Which function has two solutions? ​ (a)  

Which function has one solution? ​ (b)  

Which function has no solution? ​ (c)  

Tags

CCSS.HSA-REI.B.4B